行,所以我有這個疑問如何以適當的格式獲取這些數據?
select ss.system_step_id, ss.step_number, cd.name, ssp.system_step_product_id, p.cost, ssp.class_id from system_step ss
join system as s on s.system_id=ss.system_id
join category_description as cd on cd.category_id=ss.sub_category_id
join system_step_product as ssp on ss.system_step_id=ssp.system_step_id
join product as p on p.product_id=ssp.product_id where s.system_id = 41
order by ss.step_number, ssp.class_id;
which yields this result
7 1 Screens 808 115.0000 1
7 1 Screens 809 381.9000 2
7 1 Screens 810 441.9000 3
8 2 Printers 811 112.3200 1
8 2 Printers 812 201.0400 2
8 2 Printers 813 202.8700 3
9 3 Cash Drawers 814 135.7000 1
9 3 Cash Drawers 815 86.5400 2
9 3 Cash Drawers 816 135.7000 3
有沒有辦法把它變成三個元素的PHP數組這樣
Array
(
[0] => Array
(
[name] => "Screens"
[standard_product] => Array ([id] => 808, [price] => '115.0000')
[business_product] => Array ([id] => 809, [price] => '381.9000')
[premium_product] => Array ([id] => 810, [price] => '441.9000')
)
[1] => Array
(
[name] => "Printers"
[standard_product] => Array ([id] => 811, [price] => '112.3200')
[business_product] => Array ([id] => 812, [price] => '201.0400')
[premium_product] => Array ([id] => 813, [price] => '202.8700')
)
[2] => Array
(
[name] => "Cash Drawers"
[standard_product] => Array ([id] => 814, [price] => '135.7000')
[business_product] => Array ([id] => 815, [price] => '86.5400')
[premium_product] => Array ([id] => 816, [price] => '135.7000')
)
)
$sql = "select ss.system_step_id, ss.step_number, cd.name, ssp.system_step_product_id, p.cost, ssp.class_id, pd.name as product_name, pd.description from system_step ss join system as s on s.system_id=ss.system_id join category_description as cd on cd.category_id=ss.sub_category_id join system_step_product as ssp on ss.system_step_id=ssp.system_step_id join product as p on p.product_id=ssp.product_id join product_description as pd on pd.product_id=p.product_id where s.system_id = {$system['system_id']} order by ss.step_number, ssp.class_id;";
$result = mysql_query($sql);
$steps = array();
while($row_r = mysql_fetch_assoc($result)){
$steps[] = $row_r;
}
這樣的步驟是在全陣列9元
正如你所看到的唯一值得注意的是class_id 1是standard_product class_id 2是business_product和class_id 3是premium_product
它可以用foreach()循環完成 – 2011-05-04 21:00:08
我假設你通過類似'mysql_fetch_assoc()'的方式獲得查詢結果嗎?如果您能向我們展示您迄今爲止的代碼,那麼提供特定答案會更容易。 – 2011-05-04 21:02:10
確定我會更新我的問題 – Trace 2011-05-04 21:34:05