我想從一個mysql查詢發送一封電子郵件給用戶,並在郵件的$ message(body)中包含另一列(僱員)表:發送電子郵件給有查詢和唯一列的多個用戶
所以[email protected]應該收到一封電子郵件,只有`employee1,和Employee2,employee3在email..etc ...
這個腳本,而不是將郵件每封電子郵件中的所有行。
`employee | email`
`employee1,employee2,employee3 | [email protected]`
`employee4,employee5,employee6 | [email protected]`
`employee7,employee8,employee9 | [email protected]`
Script:
mysql_connect("localhost", "xx", "xx") or die(mysql_error());
mysql_select_db("Joomla") or die(mysql_error());
$query = sprintf("select GROUP_CONCAT(DISTINCT(e.`name`)) AS employee,
m.name as manager, email, r.week,r.year,r.manager_approved, r.Date
from peg_users e
left JOIN peg_users m ON e.manager = m.id
left JOIN project_tracker_tool_finance_report r ON m.id = r.manager
where e.project_tracker_user = 1 AND r.manager_approved = 'NO'
AND CONCAT(r.year,r.week,'') = YEARWEEK(NOW()) -2
GROUP BY m.name
order by m.name
limit 2");
//$email = "[email protected]";
$result = mysql_query($query);
while($row=mysql_fetch_array($result)) {
$email = $row['email'];
$from_email = "masked";
$emailcc = "masked";
//$emailcc = "";
$subject = "Project Time Tracker - Employees Overdue";
$headers = "From: $from_email" . "\r\n" . "CC: $emailcc";
$body .= " \n "
."Following are the people whoes subscription will expire tomorrow"." \n "."
\n "
."First Name : ".$row['employee']." \n "
."\n". "\n". "==============================". "\n";
}
// send email
if(mysql_num_rows($result) > 0)
{
$send = mail($email, $subject, $body, $headers);
}
mysql_close($conn);
**警告**:如果您只是學習PHP,請不要學習過時的['mysql_query'](http://php.net/manual/en/function.mysql-query.php)接口。這很糟糕,並且已經在PHP 7中被刪除了。像[PDO不是很難學的東西](http://net.tutsplus.com/tutorials/php/why-you-should-be-using-php-pdo- for-database-access /)以及[PHP The Right Way](http://www.phptherightway.com/)等指南有助於解釋最佳實踐。確保**你的用戶參數[妥善轉義](http://bobby-tables.com/php),否則你將以嚴重的[SQL注入漏洞](http://bobby-tables.com/ )。 – tadman
另外,如果這是一個Joomla安裝,爲什麼你不能通過Joomla API來做到這一點? – tadman