在另一個視圖中呈現視圖（不是局部視圖）

因此，我有一個ReviewsController和一個ActionResults，它在我的數據庫中查詢我的表格，並在不同視圖中返回它們，例如在另一個視圖中呈現視圖（不是局部視圖）

在ReviewsController

public ActionResult StudentWellnessReviews() 
    { 
     using (var context = new SizaFakeEntities()) 
     { 
      var userreview = context.Reviews.SqlQuery("select * from dbo.Review where WellnessService='Student Wellness Service'").ToList(); 

      return View(userreview); 
     } 
    }

而且

public ActionResult HAICUReviews() 
    { 
     using (var context = new SizaFakeEntities()) 
     { 
      var userreview = context.Reviews.SqlQuery("select * from dbo.Review where WellnessService='HAICU' ").ToList(); 

      return View(userreview); 
     } 
    }

StudentWellnessReviews查看：

<table class="table text-center width:50%"> 
       <tr> 
        <td> 
         @Html.ActionLink("Make Review", "Create", "Reviews", null, new { @class = "btn btn-success btn-sm" }) 
         @Html.ActionLink("Edit Posted Reviews", "ReviewEdit", "Reviews", null, new { @class = "btn btn-info btn-sm" }) 
        </td> 
       </tr> 


       @foreach (var item in Model) 
     { 
        <tr> 
         <td> 
          <h5>Username</h5> 
         </td> 
         <td> 
          <p><div align="left">@Html.DisplayFor(modelItem => item.Username)</div></p> 
         </td> 
        </tr> 

        <tr> 
         <td> 
          <h5>Wellness Service</h5> 
         </td> 
         <td> 
          <p><div align="left">@Html.DisplayFor(modelItem => item.WellnessService)</div></p> 
         </td> 
        </tr> 

         <tr> 
          <td> 
           <h5>Rating</h5> 
          </td> 
          <td> 
           <p><div align="left">@Html.DisplayFor(modelItem => item.Rating)</div></p> 
          </td> 
         </tr> 

         <tr> 
          <td> 
           <h5>Feedback</h5> 
          </td> 
          <td> 
           <p><div align="left"> @Html.DisplayFor(modelItem => item.Feedback)</div></p> 
          </td> 
         </tr> 
           <tr><td colspan="2"><hr class="active" /></td></tr> 

       } 

      </table>

HAICUReviews查看：

<table class="table text-center width:50%"> 
       <tr> 
        <td> 
         @Html.ActionLink("Make Review", "Create", "Reviews", null, new { @class = "btn btn-success btn-sm" }) 
         @Html.ActionLink("Edit Posted Reviews", "ReviewEdit", "Reviews", null, new { @class = "btn btn-info btn-sm" }) 
        </td> 
       </tr> 


       @foreach (var item in Model) 
     { 
        <tr> 
         <td> 
          <h5>Username</h5> 
         </td> 
         <td> 
          <p><div align="left">@Html.DisplayFor(modelItem => item.Username)</div></p> 
         </td> 
        </tr> 

        <tr> 
         <td> 
          <h5>Wellness Service</h5> 
         </td> 
         <td> 
          <p><div align="left">@Html.DisplayFor(modelItem => item.WellnessService)</div></p> 
         </td> 
        </tr> 

         <tr> 
          <td> 
           <h5>Rating</h5> 
          </td> 
          <td> 
           <p><div align="left">@Html.DisplayFor(modelItem => item.Rating)</div></p> 
          </td> 
         </tr> 

         <tr> 
          <td> 
           <h5>Feedback</h5> 
          </td> 
          <td> 
           <p><div align="left"> @Html.DisplayFor(modelItem => item.Feedback)</div></p> 
          </td> 
         </tr> 
           <tr><td colspan="2"><hr class="active" /></td></tr> 

       } 

      </table

因此，StudentWellnessReview和HAICUReviews Views顯示返回它們各自的查詢。但是我想要做的是在一個View上顯示這些查詢。你的幫助我將不勝感激。

在此先感謝

來源

2016-08-23 Moose TheTitan

要建立在肯尼斯的迴應：

你可以添加另一個動作，像這樣：在隨後

public ActionResult StudentWellnessReviewsAndHAICUReviews() 
{ 
    return View(); 
}

StudentWellnessReviewsAndHAICUReviews.cshtml：

@Html.Action("ReviewsController", "StudentWellnessReviews") 
@Html.Action("ReviewsController", "HAICUReviews")

來源

2016-08-23 22:59:04 jonh

順便說一句，正確的方式來使用它是：@ { Html.RenderAction（「StudentWellnessReviews」，「評論」）; }無需添加字控制器 –

您可以使用RenderAction：

@Html.RenderAction("ReviewsController", "StudentWellnessReviews") 
@Html.RenderAction("ReviewsController", "HAICUReviews")

來源

2016-08-23 22:24:16 Kenneth

在另一個視圖中呈現視圖（不是局部視圖）

回答

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