比賽二號文件擺脫範圍，在範圍內

Question

執行：

awk -v FILE1="FILE1.out" -v FILE2="FILE2.out" ' 
    FNR==NR {BLs[++BSize]=$1;BHs[BSize]=$2;next} {Blacked=0 for(i=1; i<BSize && ! Blacked; i++) Blacked = ($2 >= BLs[i] && $2 <= BHs[i]) 
    if (Blacked) print > FILE2 
     else print > FILE1 
    }' BlackList_B_Number.dat 2OCS_VOICECALLS_1111_11_111111 

對於這些輸入文件：

cat BlackList_B_Number.dat 

902123123 902123124 
902123127 902123128 
015    017 
450    600 

cat 2OCS_VOICECALLS_1111_11_111111 

111111111 902123124 201605 
111111111 902123125 201605 
111111111 902123126 201605 
111111111 902123126 201605 
111111111 902123123 201605 
111111111 902123123 201605 
111111111 016 201605240 
111111111 1  20160524011 
111111111 3 20160524024 
111111111 423 201605240 
111111111 5 20160524053 
111111111 470 201605240 
111111111 600 201605240 
111111111 400 424242432 

FILE2應該有470和600，但不存在，它打印在FILE1上。

cat FILE2.out 
111111111 902123124 201605 
111111111 902123123 201605 
111111111 902123123 201605 
111111111 016  201605240 

Answer 1

與預期結果

$ awk 'NR==FNR {low[NR]=$1;hi[NR]=$2;n=NR;next} 
       {for(i=1;i<=n;i++) 
        if($2>=low[i] && $2<=hi[i]) 
        {print > "inrange"; next} 
       print > "not_inrange"}' data calls 



==> inrange <== 
111111111 902123124 201605 
111111111 902123123 201605 
111111111 902123123 201605 
111111111 016 201605240 
111111111 470 201605240 
111111111 600 201605240 

==> not_inrange <== 
111111111 902123125 201605 
111111111 902123126 201605 
111111111 902123126 201605 
111111111 1  20160524011 
111111111 3 20160524024 
111111111 423 201605240 
111111111 5 20160524053 
111111111 400 424242432 

輕微重寫