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我是Android的新手,在線教程後,我遇到了TicTacToe遊戲的touchListener代碼塊問題。關於touchlistener的代碼錯誤 - Android
我不斷收到的錯誤是:
操作& &未定義的參數類型布爾,無效
下面的代碼位於MainActivity.java。我上線這個錯誤下面星強調:
// Listen for touches on the board
private OnTouchListener mTouchListener = new OnTouchListener() {
public boolean onTouch(View v, MotionEvent event) {
// Determine which cell was touched
int col = (int) event.getX()/mBoardView.getBoardCellWidth();
int row = (int) event.getY()/mBoardView.getBoardCellHeight();
int pos = row * 3 + col;
if (!mGameOver && setMove(TicTacToeGame.HUMAN_PLAYER, pos)) { //*****************
// If no winner yet, let the computer make a move
int winner = mGame.checkForWinner();
if (winner == 0) {
mInfoTextView.setText(R.string.turn_computer);
setMove(TicTacToeGame.COMPUTER_PLAYER, pos);
winner = mGame.checkForWinner();
}
}
return false;
}
};
我想這是因爲setMove()是在TicTacToeGame.java無效:
public void setMove(char player, int location) {
if (location >= 0 && location < BOARD_SIZE &&
mBoard[location] == OPEN_SPOT) {
mBoard[location] = player;
}
}
我按照精確教程http://www.harding.edu/fmccown/classes/comp475-s10/tic-tac-toe-graphics.pdf
我會非常感謝任何幫助。
非常感謝,
貝絲·安·
我已經修改setMove()來boolean: – 2013-03-14 21:02:46
private boolean setMove(char player,int location){ if(mGame.setMove(player,location)){ mBoardView.invalidate(); //重畫板 返回true; } return false; } – 2013-03-14 21:03:23
它仍然沒有工作 – 2013-03-14 21:38:20