如何將文本文件內容存儲在arrayList ..？

Question

我有文本文件如下我想將它存儲在ArrayList中，但問題是它沒有相同的鍵值對，即最後2 [參數]具有param4 = value4，param5 = value5。

如何將其存儲在arrayList或map ..？

的test.txt

[Param] 
    param1=value1 
    param2=value2 
    param3=value3 
    [Param] 
    param1=value1 
    param2=value2 
    param3=value3 
    [Param] 
    param1=value1 
    param2=value2 
    param3=value3 
    [Param] 
    param1=value1 
    param2=value2 
    param3=value3 
    [Param] 
    param1=value1 
    param2=value2 
    param3=value3 
    param4=value4 
    [Param] 
    param1=value1 
    param2=value2 
    param3=value3 
    param4=value4 
    param5=value5 

Java代碼：

public class Task { 

    static String Filepath = "C:\\Users\\Administrator\\Desktop\\TASK\\test.txt"; 
    static ArrayList<String> list1; 
    static ArrayList<String> list2; 
    static ArrayList<String> list3; 
    static HashMap<Integer, ArrayList<String>> map; 

    public static void main(String[] args) { 
     // TODO code application logic here 

     try { 
      FileInputStream fstream = new FileInputStream(Filepath); 
      BufferedReader br = new BufferedReader(new InputStreamReader(fstream)); 
      String strLine, user; 
      int lineNumber = 0; 

      list1 = new ArrayList<>(); 
      list2 = new ArrayList<>(); 
      list3 = new ArrayList<>(); 
      map = new HashMap<>(); 

      // Read File Line By Line 
      while ((strLine = br.readLine()) != null) { 
       process(strLine); 
       lineNumber++; 
      } 
     } catch (Exception e) {// Catch exception if any 
      System.err.println("Error: " + e.getMessage()); 
     } 

     map.put(1, list1); 
     map.put(2, list2); 
     map.put(3, list3); 

     for (int i = 0; i < list1.size(); i++) { 
      System.out.println("[Param]"); 
      System.out.println("param1=" + list1.get(i)); 
      System.out.println("param2=" + list2.get(i)); 
      System.out.println("param3=" + list3.get(i)); 
     } 

    } 

    public static void process(String str) { 

     if (str.contains("param1=")) { 
      String[] arr = str.split("param1="); 
      ////System.out.println(arr[1].trim()); 
      list1.add(arr[1].trim()); 
     } else if (str.contains("param2=")) { 
      String[] arr = str.split("param2="); 
      //System.out.println(arr[1].trim()); 
      list2.add(arr[1].trim()); 
     } else if (str.contains("param3=")) { 
      String[] arr = str.split("param3="); 
      //System.out.println(arr[1].trim()); 
      list3.add(arr[1].trim()); 
     } 
    }  
} 

Answer 1

你的文本文件，似乎在Windows INI文件。 ¿使用Apache Commons Configuration怎麼樣？具體來說，INIConfiguration類。