如何將此更新查詢寫入codeigniter？

Question

查詢：

$sql = "UPDATE sports SET status = 0 WHERE sport_id NOT IN (".$sport_id.") and user_id='".$user_id."'"; 

Answer 1

試試這個它的作品你...

$this->db->where_not_in('sport_id', explode(",",$sport_id)); 
$this->db->where('user_id', $user_id); 
$this->db->update("sports", array("status" => 0));