泛型類選擇XML元素值的一類性質

Question

我有一個XML這樣的：

<?xml version="1.0" encoding="utf-8" ?> 
<Property> 
    <Owner> 
    <FirstName>LeBron</FirstName> 
    <LastName>James</LastName> 
    </Owner> 
    <Seller> 
    <Name>LeBron</Name> 
    <Code>Seller01</Code> 
    <Branch>demoBranch</Branch> 
    </Seller> 
    <Equipments> 
     <Equipment> 
     <Name>Kodle</Name> 
     <CountryOfOrigin>Bryant</CountryOfOrigin> 
     </Equipment> 
     <Equipment> 
     <Name>Desktop</Name> 
     <CountryOfOrigin>Kryon</CountryOfOrigin> 
     </Equipment> 
    </Equipments> 
</Property> 

和類：

public Property() 
{ 
    public Owner owner{get;set;} 
    public Seller seller{get;set;} 
    public equipment equipment{get;set;} 
} 

public Owner 
{ 
    public FirstName{get;set;} 
    public LastName{get;set;} 
} 
public Seller 
{ 
    public Name{get;set;} 
    public Code{get;set;} 
    public Branch{get;set;} 
} 
public Equipment 
{ 
    public Name{get;set;} 
    public CountryOfOrigin{get;set;} 
} 

當然，我們可以從XML加載類一個接一個，如：

XDocument xDoc = XDocument.Load(xmlFile);  

    var owner = from e in doc.Descendants("Owner") 
       select new Owner 
       { 
        FirstName = e.Element("FirstName").Value, 
        LastName = e.Element("LastName").Value 
       }; 

或反序列化xml並獲取子類。

public Property LoadFromDocument(string fileUrl){ 
     Property serializableObject = null; 
     using(TextReader textReader = textReader = new StreamReader(fileUrl)){ 
      XmlSerializer xmlSerializer = new XmlSerializer(ObjectType); 
      serializableObject = xmlSerializer.Deserialize(textReader) as Property; 
     } 
     return serializableObject; 
    } 

然後

Owner owner = LoadFromDocument(filrUrl).Owner; 

得到業主，但我想創建一個泛型類做這樣波紋管。

public class OXmlRepository<T> 
{ 

    public XDocument xDoc { get; set; } 
    protected XName ElementName { get; private set; } 
    protected OXmlRepository() 
    { 
     ElementName = typeof(T).Name.ToString(); 
    } 

    public T GetObject() 
    { 
      //how can I get the class T instance with the values from Xml 
    } 

} 

Answer 1

public T GetObject() 
{ 
    var xs = new XmlSerializer(typeof(T)); 
    using(var reader = xDoc.CreateReader()) 
    { 
     return (T)xs.Deserialize(reader); 
    } 
}