所以我建立一個PHP頁面,並試圖在一個表中如何調整大小並顯示來自url的圖像?
目前我的代碼看起來像這樣顯示圖像:
echo "<h3>TEST TABLE</h3>";
echo "<table width='350px' border='1px'>"; //blah blah
while ($row2 = $res2->fetch_assoc()){ // takeing data from database as url is stored in mysql database
echo"<tr><td>".$row2['Name']."</td>";
echo"<td>".$row2['Description']."</td>";
$image =$row2['Img'];
$imageData = base64_encode(file_get_contents($image));
echo '<td><img src="data:image/jpeg;base64,'.$imageData.'"></td>'; //So this chunk is how I capture img from url and display
echo "<td><small>$Info</small></td></tr>";
}
echo "</table>";
我做捕獲和URL成功地顯示圖像。然而,我不太確定如何調整imgs的大小,以便像500x500左右那樣固定大小。任何意見和建議,將不勝感激!謝謝!