SQL-LIKE搜索地址字段

Question

我有SQL查詢，它在地址字段中搜索表。我的問題是在城市領域。 我假設搜索欄的街道有門牌號碼，沒有他，但我忘記了像Kolin IV，KolínII等社區的劃分。我的問題是，不知何故可以從使用SQL函數的列中僅比較城市的名稱沒有任何跡象表明該地區屬於哪個地區？

$where = " WHERE (LOWER(city) LIKE LOWER('%$fullAddress%') 
OR LOWER(street) LIKE LOWER('%$fullAddress%') 
OR CAST(postal_code AS TEXT) LIKE LOWER('%$fullAddress%') 
OR CAST(house_number AS TEXT) LIKE LOWER('%$fullAddress%') 
OR (LOWER(street || ', ' || city) LIKE LOWER('%$fullAddress%')) 
OR (LOWER(street || ' ' || CAST(house_number AS TEXT)) LIKE LOWER('%$fullAddress%')) 
OR (LOWER(city || ' ' || CAST(postal_code AS TEXT)) LIKE LOWER('%$fullAddress%')) 
OR (LOWER(street || ', ' || city || ' ' || CAST(postal_code AS TEXT)) LIKE LOWER('%$fullAddress%')) 
OR (LOWER(street || ' ' || CAST(house_number AS TEXT) || ', ' || city) LIKE LOWER('%$fullAddress%')) 
OR (LOWER(street || ' ' || CAST(house_number AS TEXT) || ', ' || city || ' ' || CAST(postal_code AS TEXT)) LIKE LOWER('%$fullAddress%'))) AND deleteby is null"; 
$results = $fce->_slctSQL("public.configurations_view", "", "services", $where, "", " ORDER BY city ASC, street ASC, house_number ASC, postal_code ASC", ""); 

Answer 1

你可能會發現，這個工程：

OR (LOWER(city || ' ' || CAST(postal_code AS TEXT)) LIKE LOWER(REPLACE('%$fullAddress%', ' ', '%')) 

然而，這可能會引入其他問題，如果城市擁有多字的名字。