有沒有什麼方法可以用GPS座標檢測地點? (儘可能不地圖)例如,如果檢查的經度和緯度是等於或接近這些:iOS - 用GPS座標檢測地點
44 35′25″n 104 42′55″w
or
44.5903 -104.7153
然後警報彈出並顯示一條消息! 謝謝。
有沒有什麼方法可以用GPS座標檢測地點? (儘可能不地圖)例如,如果檢查的經度和緯度是等於或接近這些:iOS - 用GPS座標檢測地點
44 35′25″n 104 42′55″w
or
44.5903 -104.7153
然後警報彈出並顯示一條消息! 謝謝。
你可以衡量你的 「硬編碼」 的位置和當前用戶位置之間的距離有以下幾點:
CLLocation *hardcoded_location = [[CLLocation alloc] initWithLatitude:latitude1 longitude:longitude1];
CLLocation *new_location = newLocation;
CLLocationDistance distance = [hardcoded_location distanceFromLocation:new_location];
然後,你可以這樣做:
if (distance < some_value)
{
[[[UIAlertView alloc] initWithTitle:@"Title" message:@"Message" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil, nil] show];
}
UPDATE:
typedef double CLLocationDistance
:
的距離測量(以米爲單位)從現有的位置。
此代碼將被用於解決您的問題。
CLLocation *currentLocation = newLocation;
if (currentLocation != nil)
NSLog(@"longitude = %.8f\nlatitude = %.8f", currentLocation.coordinate.longitude,currentLocation.coordinate.latitude);
// stop updating location in order to save battery power
[locationManager stopUpdatingLocation];
// Reverse Geocoding
NSLog(@"Resolving the Address");
// 「reverseGeocodeLocation」 method to translate the locate data into a human-readable address.
// The reason for using "completionHandler" ----
// Instead of using delegate to provide feedback, the CLGeocoder uses 「block」 to deal with the response. By using block, you do not need to write a separate method. Just provide the code inline to execute after the geocoding call completes.
[geocoder reverseGeocodeLocation:currentLocation completionHandler:^(NSArray *placemarks, NSError *error)
{
NSLog(@"Found placemarks: %@, error: %@", placemarks, error);
if (error == nil && [placemarks count] > 0)
{
placemark = [placemarks lastObject];
// strAdd -> take bydefault value nil
NSString *strAdd = nil;
if ([placemark.subThoroughfare length] != 0)
strAdd = placemark.subThoroughfare;
if ([placemark.thoroughfare length] != 0)
{
// strAdd -> store value of current location
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark thoroughfare]];
else
{
// strAdd -> store only this value,which is not null
strAdd = placemark.thoroughfare;
}
}
if ([placemark.postalCode length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark postalCode]];
else
strAdd = placemark.postalCode;
}
if ([placemark.locality length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark locality]];
else
strAdd = placemark.locality;
}
if ([placemark.administrativeArea length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark administrativeArea]];
else
strAdd = placemark.administrativeArea;
}
if ([placemark.country length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark country]];
else
strAdd = placemark.country;
}
是的,你可以檢測到設備何時接近某個特定位置(lat,lng)但你必須提一下接近。你不能用lat long值做簡單的普通加法和減法。你必須指定一個半徑或窗口。
distanceFromCurrentLocation = [userLocation distanceFromLocation:destinationlocation]/convertToKiloMeter;
if(distanceFromCurrentLocation < yourHigherBound && distanceFromLocation > yourLowerBound)
{
NSLog(@"yes, this place is inside my circle");
//Do the geocoding mentioned by others after this to get place name or country or whatever
}
else
{
NSLog(@"Oops!! its too far");
}
使用此方法
@interface YourClass : UIViewController
{
CLGeocoder *geocoder;
}
@end
-(void)viewDidLoad
{
geocoder = [[CLGeocoder alloc] init];
CLLocationCoordinate2D location;
location.latitude = 44.5903f;
location.longitude = -104.7153f;
[self startGeocoderWithLocation:location];
}
-(void)startGeocoderWithLocation:(CLLocationCoordinate2D)location
{
CLLocation *newLocation=[[CLLocation alloc]initWithLatitude:location.latitude longitude:location.longitude];
[geocoder reverseGeocodeLocation:newLocation completionHandler:^(NSArray *placemarks, NSError *error)
{
if (error == nil && [placemarks count] > 0)
{
CLPlacemark *placemark = [placemarks lastObject];
NSLog(@"%@",placemark.addressDictionary);
// you can use placemark.thoroughfare, placemark.locality, etc
}
else
{
//Error in finding location
}
} ];
}
公司希望它可以幫助
+1 distanceFromLocation! – satheeshwaran
好的答案,只是一個問題,如果提到'some_value'作爲米我應該剛剛提到1000CM值爲1米?或應該計算它? –
@ Mc.Lover 1m是100cm不是1000,總是以米計算 – AlexWien