的Python：「名單」對象不是可調用

Question

我有這個功能，試圖循環在一定範圍長度列表以獲得ASCII字母：

def query_execute (self,query, range): 

    list_titles = [] 
    list_colunmns_letters = [] 
    cursor.execute(query, range) 
    description = cursor.description 
    row = cursor.fetchall() 
    number_columns = len(description) 

    for word in description: 
     list_titles.append(word[0]) 

    for m in range (0,number_columns): 
     list_colunmns_letters.append(string.ascii_uppercase[m]) 

    return row,list_titles,list_colunmns_letters 

它給了我一個錯誤：

for m in range (0,number_columns):
TypeError: 'list' object is not callable

由於number_columns變量是一個整數，我不知道爲什麼這個錯誤發生，我沒有調用列表。

Answer 1

您使用range爲本地名稱由它的參數讓你的函數：

def query_execute (self,query, range): 
#        ^^^^^ 

不能再使用全球內置的名稱爲好。將參數重命名爲別的東西;我用params代替：

def query_execute (self, query, params): 
    list_titles = [] 
    list_colunmns_letters = [] 
    cursor.execute(query, range) 
    description = cursor.description 
    row = cursor.fetchall() 
    number_columns = len(description) 

    for word in description: 
     list_titles.append(word[0]) 

    for m in range(0, number_columns): 
     list_colunmns_letters.append(string.ascii_uppercase[m]) 

    return row, list_titles, list_colunmns_letters