這是一個益智遊戲,在4x4網格中必須按順序排列15個編號的圖塊。 大多數情況下,程序運行良好。但是,當將「1」數字交換到第n行,第n-2列時,程序似乎錯誤且重複了數字1.奇怪的錯誤,似乎通過添加額外的代碼行來解決。十五歲的遊戲
這裏有一個問題。當我添加的代碼的隨機行,說
int blah = 0;
或
printf("abc");
問題只是奇蹟般地消失了。
因爲我無法找到問題的根源,所以我必須發佈它的全部內容。
要只看到問題,運行不帶任何命令行參數的代碼,然後輸入隨後2加1
當我添加的代碼的隨機線在我的main()函數結束,問題消失。請嘗試一下,並幫助我瞭解發生了什麼;這真是令人困惑。
#include <stdio.h>
#include <stdlib.h>
int n=4;
int win(int board[n][n]);
void print(int board[n][n]);
int main(int argc, char * argv[])
{
if(argc != 2)
{
printf("No valid number accepted. Board size set as 4x4.\n");
}
else if(argc == 2)
{
n = atoi(argv[1]);
if(n<2 || n>5)
{
printf("No valid number accepted. Board size set as 4x4.\n");
}
else
{
printf("Preparing board of size %dx%d\n",n,n);
}
}
int board[n][n];
printf("\n The aim of the game is to sort the board so that it runs in ascending order, from 1 to %d, from left to right and up to down starting from the top left square. To make a move, enter the number of the tile you want to move. No diagonal movement is allowed.\n\n",n*n-1);
int c = n*n-1;
for(int x = 0;x<n;x++)
{
for(int y=0;y<n;y++)
{
board[x][y] = c;
c--;
}
}
if(n%2==0)
{
int temp1 = board[n-1][n-2];
board[n-1][n-2] = board[n-1][n-3];
board[n-1][n-3] = temp1;
}
print(board);
int spacex = n-1;
int spacey = n-1;
char buffer[10];
while(win(board) == 0)
{
printf("To move, enter the number you wish to move. Take note that this number must be adjacent to the blank space. Diagonal movement is not allowed.\nYour move: ");
fgets(buffer,10,stdin);
int move;
char temp[20];
if(sscanf(buffer," %d %s",&move,temp)!= 1)
{
printf("Enter a number please.\n");
continue;
}
if(move == board[spacex+1][spacey])
{
board[spacex][spacey] = board[spacex+1][spacey];
board[spacex+1][spacey] = 0;
spacex++;
}
else if(move == board[spacex-1][spacey])
{
board[spacex][spacey] = board[spacex-1][spacey];
board[spacex-1][spacey] = 0;
spacex--;
}
else if(move == board[spacex][spacey+1])
{
board[spacex][spacey] = board[spacex][spacey+1];
board[spacex][spacey+1] = 0;
spacey++;
}
else if(move == board[spacex][spacey-1])
{
board[spacex][spacey] = board[spacex][spacey-1];
board[spacex][spacey-1] = 0;
spacey--;
}
else if(move == 0)
{
printf("Enter a valid digit please.\n");
continue;
}
else
{
printf("Enter a valid number please.\n");
continue;
}
printf("\n");
print(board);
}
printf("You won!\n");
}
///////////////////////////////////////////////////////
void print(int board[n][n])
{
for(int x=0;x<n;x++)
{
for(int y=0;y<n;y++)
{
if(board[x][y] == 0)
{
printf("__ ");
}
else
printf("%2d ",board[x][y]);
}
printf("\n\n");
}
}
///////////////////////////////////////////////////////
int win(int board[n][n])
{
int check = 1;
for(int x=0;x<n;x++)
{
for(int y=0;y<n;y++)
{
if(board[x][y] != check)
{
if(x==n-1 && y == n-1);
else
{
return 0;
}
}
check++;
}
}
return 1;
}
有關代碼的任何其他意見將不勝感激。提前致謝!
快速瀏覽:你嘗試檢查相鄰瓷磚超過15拼圖的邊界。例如,當'spacex'爲0時,不應該測試索引爲'spacex-1'的左邊的瓦片。 (實際上,當你嘗試它時,你可以環繞左右邊框。) –
@M歐姆謝謝你的回答,我確實已經超出了陣列的界限。但是,添加隨機代碼行時,看似「固定」問題的解釋是什麼? –
@Quek - 未定義的行爲*任何事情都可能發生,包括產生預期的輸出。沒有必要有任何真正的解釋。 –