條件僅在第一次迭代

Question

解決下面這樣修復後的代碼，以幫助任何人，如果他們遇到了這個見面...... 原來的問題 - 只有輸入以外的整數過濾掉，而不是整數的範圍1-10之外。

lc = "abcdefghijklmnopqrstuvwxyz" #string for lc 
print("------------------------------------------------------------------------------------------------------------------------------------------------------") 

while True: 
    try: 
     passlen = int(input("How many lower case characters would you like in the password? (min 1, max 10) ")) 
     if 1<= passlen<=10: 
        a = "".join(random.sample(lc,passlen)) 
        print("") 


        counter = counter + (passlen) 
        left = 10 - counter 
        nleft = 16 - counter 
        if counter < 10: 
         print("You have used", counter, "characters. You need a minimum of", left, "characters and a maxium of", nleft, "characters to create a password of between 10 and 16 charcters.") 
         print("") 

        elif counter > 16: 
         print("You have used", counter, "charcters, more than the allowed maximum of 16 characters. Please follow the rest of the steps and retry when prompted.") 

        else: 
         print("You have used", counter, "characters, so have met the minimum amount of characters. You have a maximum of", nleft, "characters remaining to create a password with maximum 16 characters.") 
         print("") 

        break 

     else: 
      print("Input must be an integer between 1 and 10, please try again.") 
    except ValueError: 
      print("Input type must be an integer.") 

Answer 1

的問題是，當你進入範圍1-10之外的數字，它跳過while循環，你嘗試處理錯誤，特別是while passlen <1 or passlen >10:。

爲了解決這個問題，手柄第一while循環內這個邏輯，遠離第二個（省略長打印消息爲了簡潔）的。例如。

while True: 
    try: 
     passlen = int(input("How many lower case characters would you like in the password? (min 1, max 10) ")) 
     if 1 <= pathlen <= 10: 
      break 
     else: 
      print("Input must be an integer between 1 and 10, please try again.") 
    except ValueError: 
     print("Input type not recognized")