總和查詢的最大值

我在嘗試編寫一個查詢，列出以最大總信用點數註冊的學生。總和查詢的最大值

這裏是我的查詢：

SELECT s.S_ID, 
     s.S_LAST, 
     s.S_FIRST, 
     s."Total Credits" 
FROM 
    (SELECT q2.S_ID, 
      q2.S_LAST, 
      q2.S_FIRST, 
      sum(q1.CREDITS) "Total Credits" 
    FROM 
    (SELECT COURSE_NO, 
      CREDITS 
     FROM COURSE) q1 
    JOIN 
    (SELECT s.S_ID, 
      s.S_LAST, 
      s.S_FIRST, 
      cs.COURSE_NO 
     FROM STUDENT s 
     JOIN ENROLLMENT e ON s.S_ID = e.S_ID 
     JOIN COURSE_SECTION cs ON e.C_SEC_ID = cs.C_SEC_ID) q2 ON q1.COURSE_NO = q2.COURSE_NO 
    GROUP BY q2.S_ID, 
      q2.S_LAST, 
      q2.S_FIRST) q3 
GROUP BY s.S_ID, 
     s.S_LAST, 
     s.S_FIRST, 
     s."Total Credits" 
WHERE "Total Credits" = max("Total Credits");

這不起作用，我收到此錯誤：

ORA-00933: SQL command not properly ended 
00933. 00000 - "SQL command not properly ended" 
*Cause: 
*Action: 
Error at Line: 23 Column: 1

任何幫助將不勝感激。

來源

2014-05-22 user3664923

你的外選擇和'q3'不是從's'和你上次'where'條款不正確，您使用的 –

的數據庫？你想要所有學分最高的學生嗎？ – Bohemian

這是使用Oracle SQL Developer。是的，我想要所有學分最高的學生，而不僅僅是一個。 – user3664923

SELECT q3.S_ID, 
     q3.S_LAST, 
     q3.S_FIRST, 
     max(q3.Total Credits) 
FROM 
    (SELECT q2.S_ID, 
      q2.S_LAST, 
      q2.S_FIRST, 
      sum(q1.CREDITS) Total Credits 
    FROM 
    (SELECT COURSE_NO, 
      CREDITS 
     FROM COURSE) q1 
    JOIN 
    (SELECT s.S_ID, 
      s.S_LAST, 
      s.S_FIRST, 
      cs.COURSE_NO 
     FROM STUDENT s 
     JOIN ENROLLMENT e ON s.S_ID = e.S_ID 
     JOIN COURSE_SECTION cs ON e.C_SEC_ID = cs.C_SEC_ID) q2 ON q1.COURSE_NO = q2.COURSE_NO 
    GROUP BY q2.S_ID, 
      q2.S_LAST, 
      q2.S_FIRST) q3 
GROUP BY q3.S_ID, 
     q3.S_LAST, 
     q3.S_FIRST;

來源

2014-05-22 12:33:23 user3635169

這仍然是不正確的 –

是的，這不起作用，對不起。 – user3664923

有關我如何完成這項工作的任何其他建議？ – user3664923

您可能希望通過只使用GROUP BY和點心（）來解決這個問題，並與ORDER BY和（）與限制1或更多，這取決於有多少學生檢索結果你想要的。

這將消除外部子查詢。

來源

2014-05-22 12:48:22 Mercutio

頑皮的同一個問題的雙重張貼！這是我給你的其他帖子的答案，同樣的東西在這裏仍然適用。

我敢肯定（沒有預言機來測試這一點），你的別名是這個問題：

sum(q1.CREDITS) Total Credits

應該

sum(q1.CREDITS) "Total Credits"

也因此

max(q3.Total Credits)

應該be

max(q3."Total Credits")

或者你可以擺脫別名中的空間。但是可能還有更多的東西，正如我所說的，我沒有Oracle機器可以方便地測試。

來源

2014-05-22 14:29:10

刪除所有的「噪音」您的查詢變得

SELECT s.S_ID, s.S_LAST, s.S_FIRST, s."Total Credits" 
FROM 
    (SELECT ... 
    FROM (...) q1 
    JOIN (...) q2 
) q3 
GROUP BY s.S_ID, s.S_LAST, s.S_FIRST, s."Total Credits" 
WHERE "Total Credits" = max("Total Credits");

可以很容易地看到，s是不是從你的主查詢可見，同樣在你面對與聚合的詳細WHERE條件，這是不可能（至少不是這樣）

來源

2014-05-22 15:04:22 Serpiton

如果你一次建立一個查詢，你會注意到，首先，你不需要任何這些內聯視圖。你可以用一個CTE定義和一個子查詢簡單地完成它。

WITH 
student AS 
(SELECT 1 s_id, 'Jones' s_last, 'Sally' s_first FROM dual UNION ALL 
    SELECT 2, 'Smith', 'Pete' FROM dual UNION ALL 
    SELECT 3, 'DeThroned', 'Kate' FROM dual 
), 
enrollment AS 
(SELECT 1 s_id, 10 c_sec_id FROM dual UNION ALL 
    select 1, 11 FROM dual UNION ALL 
    select 2, 11 FROM dual UNION ALL 
    SELECT 3, 12 FROM dual 
), 
course_section AS 
(SELECT 10 c_sec_id, 101 course_no FROM dual UNION ALL 
    SELECT 11, 102 FROM dual UNION ALL 
    SELECT 12, 103 FROM dual 
), 
course AS 
(SELECT 101 course_id, 1 credits FROM dual UNION ALL 
    SELECT 102, 2 FROM dual UNION ALL 
    SELECT 103, 3 FROM dual 
), 
StudentCredit AS 
(SELECT s.s_id, s_last, s_first, sum(c.credits) AS TotalCredits 
    FROM student s 
    JOIN enrollment e 
    ON e.s_id = s.s_id 
    JOIN course_section cs 
    ON cs.c_sec_id = e.c_sec_id 
    JOIN course c 
    ON c.course_id = cs.course_no 
    GROUP BY s.s_id, s_last, s_first 
) 
SELECT * 
FROM StudentCredit 
WHERE TotalCredits = (
      SELECT MAX(TotalCredits) 
      FROM StudentCredit 
     );

來源

2014-05-24 01:19:36 TommCatt

總和查詢的最大值

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