1
我知道這是一個簡單的問題,所以道歉,但我是新來的LINQ to XML,並因與以下困難:的LINQ to XML decendant元素
我有以下的XML,我試圖擺脫所有元素,包括地址要素:
<LawCentres>
<LawCentre>
<LawCentreID>2</LawCentreID>
<LawCentreName>Test Law Centre</LawCentreName>
<Address>
<Address1>Test Address1</Address1>
<Address2>Test Address2</Address2>
<Address3>Test Address3</Address3>
</Address>
</LawCentre>
<LawCentre>
<LawCentreID>22</LawCentreID>
<LawCentreName>Secondary Law Centre</LawCentreName>
<Address>
<Address1>ADDRESS11</Address1>
<Address2>ADDRESS21</Address2>
<Address3>ADDRESS31</Address3>
<CountryRef>10985</CountryRef>
<CountyRef>12116</CountyRef>
</Address>
</LawCentre>
</LawCentres>
和我有下面的代碼寫的,但我有difficuty法律中心信息沿着提取地址: 的XDocument lawCentres = XDocument.Load(服務器.MapPath( 「XML \ LawCentres.xml」));
var lawCentreQuery = from c in lawCentres.Descendants("LawCentre")
where (int)c.Element("LawCentreID") == lawCentreID
select new LawCentre
{
LawCentreName = (string)c.Element("LawCentreName"),
LawCentreID = (int)c.Element("LawCentreID"),
LawCentreAddressLine1 = (string)c.Element("Address1"),
LawCentreAddressLine2 = (string)c.Element("Address2"),
LawCentreAddressLine3 = (string)c.Element("Address3"),
};
任何想法?
第二個選項可以完美取代
(string)c.Element("Address1")
,您的幫助哈桑萬分感謝! – Alicia@Alicia第一個選項有路徑錯誤;修復。現在,這也會起作用 –