0
我正在嘗試按字母順序排列用戶輸入,最多10,000個單詞,最大長度爲25個單詞。我正在使用「停止」來提前終止用戶輸入,這會使我陷入一些問題。下面爲輸出當前程序的結果,當我嘗試輸入你好停止按字典返回記憶字符對用戶輸入進行排序?
▒l▒
0▒l▒
A{▒
e▒
▒&
▒▒
▒▒
▒▒
▒▒
▒l▒
▒l▒
▒▒;
▒Se▒
▒
▒
▒
▒
▒!
Ќl▒
▒
▒
▒
▒.X
▒
我假定這是與我的內存分配做,但我也不太清楚,但沒有找到對此一些答案。任何幫助,將不勝感激,下面是我的代碼
#include<stdio.h>
#include <string.h>
//for using tolower
#include <ctype.h>
int main() {
int i, k, j;
char abc[25];
const char *stop = "stop";
char *p; //using for lowercase
//using 2d array for max of 10,000 words, max size of words 25
char str[10000][25], temp[25];
printf("Enter up to 10000 words, type stop to enter the current words:\n");
while (strncmp(abc, "stop", 5) != 0) {
scanf("%s", abc);
}
//for (i = 0; i < 10000; ++i)
//scanf("%s[^\n]", str[i]);
for (i = 0; i < 10000; ++i)
for (k = i + 1; k < 10000; ++k) {
//comparing two strings using strcmp() function is used
//using strcpy() to copy string to a temp
if (strcmp(str[i], str[k]) > 0) {
strcpy(temp, str[i]);
strcpy(str[i], str[k]);
strcpy(str[k], temp);
}
}
//using pointer to converting to lowercase
//src: https://www.daniweb.com/programming/software-development/threads/57296/how-does-one-tolower-an-entire-string
for (p = str; *p != '\0'; p++)
*p = (char) tolower(*p);
//printing words in lexi order
printf("\nWords in lexicographical order: \n");
for (i = 0; i < 10000; ++i) {
puts(str[i]);
}
printf("WARNING: Words longer than 25 in length were ignored. \n");
return 0;
}
不保存輸入將字符串轉換爲'str'數組。 – BLUEPIXY
另外,'while'循環首次運行時,'abc'沒有初始化。在發佈問題之前,打開您的編譯器警告並修復所有這些警告。並學會使用調試器。如果您使用過調試器,問題應該清楚。 – kaylum
@WhozCraig那諷刺真的有必要嗎?另外,'datum'在你的句子中不正確。它應該是複數的「數據」。 – DIMMSum