SQL選擇組織樹（層次結構）的查詢

我有一個這樣的表;SQL選擇組織樹（層次結構）的查詢

CREATE TABLE [dbo].[TH_ORGANIZATION] 
(
    [ID_CORGANIZATION] [decimal](18, 0) IDENTITY(1,1) NOT NULL, 
    [ID_CCOMPANY] [nvarchar](10) NOT NULL, 
    [CORGANIZATION_NAME_tr] [nvarchar](100) NULL, 
    [CORGANIZATION_NAME_en] [nvarchar](100) NULL, 
    [CORGANIZATION_MAN_ID_CEMP] [decimal](10, 0) NULL, 
    [CORGANIZATION_UPLINK_ID] [decimal](18, 0) NULL, 
    [CACTIVE] [bit] NOT NULL CONSTRAINT [DF_TH_ORGANIZATION_CACTIVE] DEFAULT ((1)), 

    CONSTRAINT [PK_TH_ORGANIZATION] 
     PRIMARY KEY CLUSTERED ([ID_CORGANIZATION] ASC) 
      WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, 
       IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, 
       ALLOW_PAGE_LOCKS = ON) ON [PRIMARY] 
) ON [PRIMARY] 
GO

現在我想寫一個SQL查詢來獲取我的組織樹。主欄爲ID_CORGANIZATION，子組織與CORGANIZATION_UPLINK_ID欄連接同一張表。

任何想法？

現在最好的解決辦法是

WITH temp as(SELECT * FROM TH_ORGANIZATION WHERE ID_CORGANIZATION = '3' UNION ALL SELECT ei.* FROM TH_ORGANIZATION ei INNER JOIN temp x ON ei.CORGANIZATION_UPLINK_ID = x.ID_CORGANIZATION ") SELECT * FROM temp

來源

2015-08-21 user5192770

[SQL很好地檢索樹結構]的可能重複（http://stackoverflow.com/questions/3555101/sql-to-retrieve-tree-structure-nicely） –

SELECT * FROM TH_ORGANIZATION As O, 
    TH_ORGANIZATION As Sub 
WHERE O.ID_CORGANIZATION 
    = Sub.CORGANIZATION_UPLINK_ID;

你會得到組織的列表，及其子機構，遞歸。當然你也可以訂購清單。

如果你想在所有的一列，你可以使用一個外部聯接這樣的（因此只選擇O. *）：

SELECT O.* FROM th_organization As O 
LEFT OUTER JOIN th_organization As Sub 
ON O.id_corganization 
    = Sub.corganization_uplink_id;

示例（我使用的縮寫），你應該得到這樣的名單：

我發現

id_c uplink_id name 
    1    OrgA 
    2    OrgB 
11  1  subA 
12  1  subB 
21  2  sub2 
111  11  subsubA

來源

2015-08-21 21:41:41

您的查詢不適合我。我最好的查詢是「WITH temp as（SELECT * FROM TH_ORGANIZATION WHERE ID_CORGANIZATION ='3'UNION ALL SELECT ei。* FROM TH_ORGANIZATION ei INNER JOIN temp x ON ei.CORGANIZATION_UPLINK_ID = x.ID_CORGANIZATION ）SELECT * FROM temp sql + = @「WHERE ID_CCOMPANY = @ idCompany」; sql + = @「ORDER BY CORGANIZATION_SORTNO」; – user5192770

我最好的解決辦法：

WITH temp as(SELECT * FROM TH_ORGANIZATION WHERE ID_CORGANIZATION = '3' UNION ALL SELECT ei.* FROM TH_ORGANIZATION ei INNER JOIN temp x ON ei.CORGANIZATION_UPLINK_ID = x.ID_CORGANIZATION ") SELECT * FROM temp

注： '3' 我開始組織ID

來源

2015-08-24 19:48:33 user5192770

SQL選擇組織樹（層次結構）的查詢

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