替換使用替代

Question

的地圖上串多個單詞我有地圖替換

val replacements = Map("aaa" -> "d", "bbb" -> "x", "ccc" -> "mx")

我想更換每個地圖鍵的所有出現相應值的字符串中。

val str = "This aaa is very bbb and I would love to cccc" 
val result = cleanString(str, replacements) 
result = "This d is very x and I would love to mx" 

我已經做了

val sb = new StringBuilder(str) 
for(repl <- replacements.keySet) yield { 
    sb.replaceAllLiterally(repl, replacement.get(repl)) 
} 

，但我想更多的東西的功能就像一個map或fold，我申請到字符串的函數返回另一個字符串，而無需被裏面修改一個可變變量循環。

Answer 1

一個選擇：在Map使用foldLeft與str爲初始參數：

replacements.foldLeft(str)((a, b) => a.replaceAllLiterally(b._1, b._2)) 
// res8: String = This d is very x and I would love to mxc 

Answer 2

我真的不喜歡這一點，但它應該工作：

str.split(" ").toList.map { s => 
    if(replacements.get(s).isDefined) { 
    replacements(s) 
    } else { 
    s 
    } 
}.mkString(" ")