如何在一組總和中顯示0？

Question

我試圖創建一個交叉，但我需要一個類型的查詢，通過cia_ensures

我的表重複每個policy_business_unit組：

|policies| 
    |id| |client| |policy_business_unit_id| |cia_ensure_id| |state|  
    1  MATT     1     1    0 
    2  STEVE     1     2    1 
    3  BILL     1     3    2 
    4  LARRY     1     4    0 

|policy_business_units| 
    |id| |name| |comercial_area_id| 
    1  LIFE   1 

|comercial_areas| 
    |id| |name| 
    1  BANK 

|cia_ensures| 
    |id| |name| 
    1  SPRINT 
    2  APPLE 
    3  PEPSI 
    4  ORANGE 
    5  BT 

這裏是信息：

http://sqlfiddle.com/#!2/37690/2 

我試圖使用所有cia_ensures顯示計算結果：

SELECT ce.name AS CIAS, pb.name AS UNIT, 
    SUM(CASE WHEN p.state =0 THEN 1 ELSE 0 END) AS ACTIVES, 
    SUM(CASE WHEN p.state =1 THEN 1 ELSE 0 END) AS INACTIVES, 
    SUM(CASE WHEN p.state =2 THEN 1 ELSE 0 END) AS OTHERS 
From policies p 
    INNER JOIN policy_business_units pb ON pb.id = p.policy_business_unit_id 
    INNER JOIN comercial_areas ca ON ca.id = pb.comercial_area_id 
    INNER JOIN cia_ensures ce ON ce.id = p.cia_ensure_id 
WHERE policy_business_unit_id IN (1) 
GROUP BY cia_ensure_id 

我得到這個結果：

UNIT    CIAS  COMERCIAL_AREAS STATE_0 STATE_1 STATUS_2 
LIFE   SPRINT  BANK     1  0   0 
LIFE   APPLE  BANK     0  1   0 
LIFE   PEPSI  BANK     0  0   1 
LIFE   ORANGE  BANK     1  0   0 

這裏是我的問題： 我想告訴所有cia_ensure_id，如果這沒有關係顯示0

我該怎麼做纔能有這樣的結果？

UNIT    CIAS  COMERCIAL_AREAS STATE_0 STATE_1 STATUS_2 
LIFE   SPRINT  BANK     1  0   0 
LIFE   APPLE  BANK     0  1   0 
LIFE   PEPSI  BANK     0  0   1 
LIFE   ORANGE  BANK     1  0   0 
LIFE   BT   BANK     0  0   0 

我試圖

SELECT ce.name AS CIAS, pb.name AS UNIT, 
    SUM(CASE WHEN p.state =0 THEN 1 ELSE 0 END) AS ACTIVES, 
    SUM(CASE WHEN p.state =1 THEN 1 ELSE 0 END) AS INACTIVES, 
    SUM(CASE WHEN p.state =2 THEN 1 ELSE 0 END) AS OTHERS 
From policies p 
    INNER JOIN policy_business_units pb ON pb.id = p.policy_business_unit_id 
    INNER JOIN comercial_areas ca ON ca.id = pb.comercial_area_id 
    INNER JOIN cia_ensures ce ON ce.id = p.cia_ensure_id 
WHERE policy_business_unit_id IN (1) AND cia_ensured_id IN (1,2,3,4,5) 
GROUP BY cia_ensure_id 

所有形式的幫助將被接受。

請給我所有的幫助。

謝謝。

Answer 1

SELECT ce.name AS CIAS, pb.name AS UNIT, 
    SUM(CASE WHEN p.state =0 THEN 1 ELSE 0 END) AS ACTIVES, 
    SUM(CASE WHEN p.state =1 THEN 1 ELSE 0 END) AS INACTIVES, 
    SUM(CASE WHEN p.state =2 THEN 1 ELSE 0 END) AS OTHERS 
From policies p 
    INNER JOIN policy_business_units pb ON pb.id = p.policy_business_unit_id 
    INNER JOIN comercial_areas ca ON ca.id = pb.comercial_area_id 
    RIGHT JOIN cia_ensures ce ON ce.id = p.cia_ensure_id 
WHERE (policy_business_unit_id IN (1) or policy_business_unit_id is null) 
GROUP BY cia_ensure_id 

將內部更改爲右側，如果它位於其他表之前，則可以留下，因爲它是最後一個表。基本上你需要CIA的所有記錄，只有那些在其他表格中匹配的記錄。

請注意，您還必須在policy_business_Unit上查找空值，否則（1）會排除右連接添加的行。

或移動標準的加入讓這只是加入

SELECT ce.name AS CIAS, pb.name AS UNIT, 
    SUM(CASE WHEN p.state =0 THEN 1 ELSE 0 END) AS ACTIVES, 
    SUM(CASE WHEN p.state =1 THEN 1 ELSE 0 END) AS INACTIVES, 
    SUM(CASE WHEN p.state =2 THEN 1 ELSE 0 END) AS OTHERS 
From policies p 
    INNER JOIN policy_business_units pb 
    ON pb.id = p.policy_business_unit_id 
    and policy_business_unit_id IN (1) 
    INNER JOIN comercial_areas ca ON ca.id = pb.comercial_area_id 
    RIGHT JOIN cia_ensures ce ON ce.id = p.cia_ensure_id 
GROUP BY cia_ensure_id 

假設所有NULL PB.names可以閱讀「生活」則改變第一選擇線讀之前應用的行...但是這對我來說是一個糟糕的假設。所以除非有一條規則來管理這個，否則null應該是基於設計的有效響應。

SELECT ce.name AS CIAS, coalesce(pb.name,'LIFE') AS UNIT,