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我對Web服務非常陌生,我想知道如何將wsdl:type節中定義的類型保存到它自己的模式中,並且可以在多個WSDL中重用該模式。我一直在嘗試按照以下方式使用導入聲明,但這並不是非常成功。如何分離WSDL中的嵌入式模式?
<wsdl:types>
<xsd:schema targetNamespace="http://ttdev.com/ss">
<xsd:import namespace="http://ttdev.com/ss"schemaLocation="http://ttdev.com/ss/SimpleService.xsd"/>
</xsd:schema>
</wsdl:types>
<wsdl:definitions
xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:tns="http://ttdev.com/ss" xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" name="SimpleService" targetNamespace="http://ttdev.com/ss" xmlns:xi="http://www.w3.org/2001/XInclude">
<wsdl:types>
<xsd:schema targetNamespace="http://ttdev.com/ss">
<xsd:element name="concatRequest">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="param1" type="xsd:string"/>
<xsd:element name="param2" type="xsd:string"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
<xsd:element name="concatResponse">
<xsd:complexType>
<xsd:sequence minOccurs="0" maxOccurs="100">
<xsd:element name="name" type="xsd:string"/>
<xsd:element name="description" type="xsd:string"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:schema>
</wsdl:types>
<wsdl:message name="concatRequest">
<wsdl:part name="parameters" element="tns:concatRequest"/>
</wsdl:message>
<wsdl:message name="concatResponse">
<wsdl:part name="parameters" element="tns:concatResponse"/>
</wsdl:message>
<wsdl:portType name="SimpleService">
<wsdl:operation name="concat">
<wsdl:input message="tns:concatRequest"/>
<wsdl:output message="tns:concatResponse"/>
</wsdl:operation>
</wsdl:portType>
<wsdl:binding name="SimpleServiceSOAP" type="tns:SimpleService">
<soap:binding style="document" transport="http://schemas.xmlsoap.org/soap/http"/>
<wsdl:operation name="concat">
<soap:operation soapAction="http://ttdev.com/ss/NewOperation"/>
<wsdl:input>
<soap:body use="literal"/>
</wsdl:input>
<wsdl:output>
<soap:body use="literal"/>
</wsdl:output>
</wsdl:operation>
</wsdl:binding>
<wsdl:service name="SimpleService">
<wsdl:port name="p1" binding="tns:SimpleServiceSOAP">
<soap:address location="http://localhost:8080/ss/p1"/>
</wsdl:port>
</wsdl:service>
</wsdl:definitions>
總結:
- 我已經分離的模式到它自己的文件SinpleService.xsd(按照以下示例代碼)
- 我添加導入語句到WSDL按照上述。
- 但是,當我通過導入引用類型時,看起來類型無法解析。
<?xml version="1.0"?>
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:ns1="http://schemas.xmlsoap.org/soap/encoding/" xmlns:ns2="http://ttdev.com/ss" targetNamespace="http://ttdev.com/ss">
<xsd:import namespace="http://schemas.xmlsoap.org/soap/encoding/" schemaLocation="http://schemas.xmlsoap.org/soap/encoding/"/>
<xsd:import namespace="http://www.w3.org/2001/XMLSchema"/>
<xsd:element name="concatRequest">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="param1" type="xsd:string"/>
<xsd:element name="param2" type="xsd:string"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
<xsd:element name="concatResponse">
<xsd:complexType>
<xsd:sequence minOccurs="0" maxOccurs="100">
<xsd:element name="name" type="xsd:string"/>
<xsd:element name="description" type="xsd:string"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:schema>
`import`是正確的做法,堅持下去。告訴我們爲什麼它不起作用。 – skaffman 2011-01-09 22:00:02
WSDL未通過驗證,這是我回來的錯誤: C:\ Users \ User \ workspace \ Axis2SimpleService \ src \ main \ resources \ SimpleService.wsdl無效。字符's'在語法上是意想不到的原因:預期下列之一'/>''>'詳細信息XML生產:生產'元素'不滿意 – user465374 2011-01-09 22:03:22