2017-10-13 80 views
2

我在追蹤這段代碼,我試圖弄清楚它應該做什麼。我無法讓它在IntelliJ上運行。即使我定義了Project SDK,運行選項也是灰色的。但我只想知道代碼應該做什麼。Java多線程示例在不同線程上打印100次消息?

我剛剛讀了一些關於線程的理論。是不是應該在不同的線程上用時間戳顯示每條消息100次?而Runnable 4是一個如何使用lambda正確的例子?

主類

import java.util.Date; 
import java.util.concurrent.*; 

public class Example02 
{ 
    public static void main(String []args) 
    { 
     // create runnables 
     PrintMessageRunnable pmRunnable1 = new PrintMessageRunnable("Runnable 1"); 
     PrintMessageRunnable pmRunnable2 = new PrintMessageRunnable("Runnable 2"); 
     PrintMessageRunnable pmRunnable3 = new PrintMessageRunnable("Runnable 3"); 

     // passing a runnable using Lambda notation 
     Runnable pmRunnable4 =() -> { 
      // this is the code inside the run method 
      String message = "Lambda Runnable"; 
      int REPETITIONS = 100; 
      int DELAY = 100; 

      try { 
       for(int i = 1; i <= REPETITIONS; i++) { 
        Date now = new Date(); 
        System.out.println(now + ": " + message + "." + i); 
        Thread.sleep(DELAY); 
       } 
      } 
      catch (InterruptedException e) { 
       System.out.println("Runnable version interrupted."); 
      } 
     }; 

     // specify how many threads the executor service should manage 
     int MAX_THREADS = 2; 
     ExecutorService pool = Executors.newFixedThreadPool(MAX_THREADS); 

     // start running 
     pool.execute(pmRunnable1); 
     pool.execute(pmRunnable2); 
     pool.execute(pmRunnable3); 
     pool.execute(pmRunnable4); 
    } 
} 

打印信息運行的類

import java.util.*; 

public class PrintMessageRunnable implements Runnable 
{ 
    private String message; 
    private int REPETITIONS = 100; 
    private int DELAY = 100; 

    public PrintMessageRunnable(String message){ 
     this.message = message; 
    } 

    public void run(){ 
     try { 
      for(int i = 1; i <= REPETITIONS; i++) { 
       Date now = new Date(); 
       System.out.println(now + ": " + message + "." + i); 
       Thread.sleep(DELAY); 
      } 
     } 
     catch (InterruptedException e) { 
      System.out.println("Runnable version interrupted."); 
     } 
    } 
} 

回答

1

在你的榜樣,你有2個線程與時間戳打印您的消息。 runnable的lambda表示也是正確的。

java.util.Date的使用是危險的,因爲它不是線程安全的。 在多線程應用程序中使用LocalDateTime以避免錯誤

+0

謝謝:)我只是在閱讀有關使用鎖使線程安全的事情。現在就通過舉例說明。 – Torque

+0

單個'Date'實例在這裏不會被多個線程使用。所以這是非常安全的。 – Henry

+0

如果一個對象實例不被多個線程使用,則不需要考慮線程安全。 – Alex