刪除特定字符之間的字符在PL/SQL

Question

我需要從下面的例子

luvi.luci@gma

得到一個子，我想回到熒光素酶。所以基本上我需要在'之前刪除所有的信息'。並 '@'

更多的例子後：

pd.prd@gded

Answer 1

你可以用regexp_substr()做到這一點。這裏有一個例子：

select translate(regexp_substr(email, '[.].*@', 1, 1), 'x.@', 'x') 
from (select 'luvi.luci@gma' as email from dual) x 

Answer 2

with data (val) as 
(
    select null from dual union all 
    select 'luvi.luci' from dual union all 
    select 'luvi.luci@gma' from dual union all 
    select 'pd.prd@gded' from dual 
) 
-- step:1 
-- find the second group (\2) within the match 
-- ie. (any word/sequence of characters (\w+) flanked by a dot and a @) 
-- step:2 
-- |. OR any other character not matched in step:1 - will be ignored 
-- step:3 
-- \2 for each match found while parsing, for the entire match, 
--  replace it with the second group - so the dot and the @ are dropped from the match 
select val, regexp_replace (val, '(\.(\w+)@)|.', '\2') ss from data;