Python - 積極地 - 結合泡沫和等值線地圖

Question

在對這個問題R - plotly - combine bubble and chorpleth map的回答中，很好地描述瞭如何在一張地圖內積極地組合泡泡和等值線圖。我想在Python中複製完全相同的示例，但我沒有根據劇情文檔（https://plot.ly/python/reference/）中提供的信息進行管理。

等效R代碼裏面的內容如下：

lon = c(-73.9865812, -118.2427266, -87.6244212, -95.3676974) 
pop = c(8287238, 3826423, 2705627, 2129784) 
df_cities = data.frame(cities, lat, lon, pop) 

state_codes = c("NY", "CA", "IL", "TX") 
pop = c(19746227.0, 38802500.0, 12880580.0, 26956958.0) 
df_states = data.frame(state_codes, pop) 

plot_ly(df_cities, lon=lon, lat=lat, 
     text=paste0(df_cities$cities,'<br>Population: ', df_cities$pop), 
     marker= list(size = sqrt(pop/10000) + 1), type="scattergeo", 
     filename="stackoverflow/choropleth+scattergeo") %>% 
    add_trace(z=df_states$pop, 
      locations=df_states$state_codes, 
      text=paste0(df_states$state_codes, '<br>Population: ', df_states$pop), 
      type="choropleth", 
      colors = 'Purples', 
      locationmode="USA-states") %>% 
    layout(geo = list(scope="usa")) 

這怎麼能在Python中實現？

Answer 1

只需將.py附加到圖表的URL（例如https://plot.ly/~RPlotBot/1735.py）即可查看相應的Python代碼。

Answer 2

我發現，我不得不調整R代碼只是一點點得到它的工作：

cities = c('New York', 'Los Angeles', 'Chicago', 'Houston') 
lat = c(40.7305991, 34.053717, 41.8755546, 29.7589382) 
lon = c(-73.9865812, -118.2427266, -87.6244212, -95.3676974) 
pop = c(8287238, 3826423, 2705627, 2129784) 
df_cities = data.frame(cities, lat, lon, pop) 

state_codes = c("NY", "CA", "IL", "TX") 
pop = c(19746227.0, 38802500.0, 12880580.0, 26956958.0) 
df_states = data.frame(state_codes, pop) 

plot_ly(df_cities, lon=lon, lat=lat, 
     text = paste0(df_cities$cities,'<br>Population: ', df_cities$pop), 
     marker = list(size = sqrt(pop/10000) + 1), type="scattergeo", 
     filename = "stackoverflow/choropleth+scattergeo") %>% 
add_trace(z=df_states$pop, 
    locations = df_states$state_codes, 
    text = paste0(df_states$state_codes, '<br>Population: ', df_states$pop), 
    type = "choropleth", 
    colors = 'Purples', 
    locationmode = "USA-states") %>% 
layout(geo = list(scope="usa"))