PHP此錯誤代碼的錯誤

Question

我是PHP新手，最近一直在學習構建表單。我能夠讓他們繼續並運行，並按照教程網站上的指示進行操作。但是，這個形式我試圖通過輸入代碼來建立自己的代碼，我記得我在w3c網站學到了。我無法運行它。請幫我..

這是形式的HTML代碼：

<form name="contactform" method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" id="contactform"> 

<label for="first_name">First Name<span class="error">*<?php echo $first_nameErr;?></span></label><br> 

<input type="text" name="first_name" maxlength="50" size="20" value="<?php echo $first_name;?>"><br> 

<label for="last_name">Last Name<span class="error">*<?php echo $last_nameErr;?></span></label><br> 

<input type="text" name="last_name" maxlength="50" size="20" value="<?php echo $last_name;?>"><br> 

<label for="email">Email Address<span class="error"><?php echo $emailErr;?>*</span></label><br> 

<input type="text" name="email" maxlength="80" size="35" value="<?php echo $email;?>"><br> 

<label for="overview">Overview of project <span class="error">*&nbsp;<?php echo $overviewErr;?></span></label><br> 

<textarea name="overview" maxlength="1000" cols="25" rows="5"><?php echo $overview;?></textarea><br> 

<br>&nbsp;<input type="submit" value="Submit" name="submit" class="art-button" style="zoom: 1;">&nbsp; 
</form> 

這是形式的PHP代碼，這是同一個文件的HTML代碼中：

<?php 

function test_input($data){ 

    $data = trim($data); 
    $data = stripslashes($data); 
    $data = htmlspecialchars($data); 

    return $data; 
} 

function clean_string($string) { 

    $bad = array("content-type","bcc:","to:","cc:","href"); 
    return str_replace($bad,"",$string); 

} 


// define variables and set to empty values 
$first_nameErr = $last_nameErr = $emailErr = $overviewErr = ""; 
$first_name = $last_name = $email = $overview = ""; 

if(isset($_POST['email'])) { 

$email_to = "myself@mydomain.com"; 
$email_subject = "Contact us - My company's name"; 
{ 

if (empty($_POST["first_name"])) 
{$first_nameErr = "(First Name is required)";} 

else 
{$first_name = test_input($_POST["first_name"]); 

// check if name only contains letters and whitespace 
if (!preg_match("/^[a-zA-Z ]*$/",$first_name)) 
     { 
     $first_name = "(Only letters and white space allowed)"; 
     } 
    } 

if (empty($_POST["last_name"])) 
{$last_nameErr = "(Last Name is required)";} 

else 
    {$last_name = test_input($_POST["last_name"]); 

// check if name only contains letters and whitespace 
if (!preg_match("/^[a-zA-Z ]*$/",$last_name)) 
     { 
     $last_name = "(Only letters and white space allowed)"; 
     } 
    } 

if (empty($_POST["email"])) 
    {$emailErr = "(Email ID is required)";} 

else 
    {$email = test_input($_POST["email"]); 

// check if e-mail address syntax is valid 
    if (!preg_match("/([\w\-]+\@[\w\-]+\.[\w\-]+)/",$email)) 
     { 
     $emailErr = "(Invalid email format)"; 
     } 
    } 

if (empty($_POST["overview"])) 
    {$overviewErr = "(Overview is required)";} 

else 
    {$overview = test_input($_POST["overview"]); 

// check if name only contains letters and whitespace 
    if (!preg_match("/^[a-zA-Z ]*$/",$overview)) 
     { 
     $overview = "(Only letters and white space allowed)"; 
     } 
    } 

} 

//Email & SEND INFO 
$email_message = "Form details below.\n\n"; 

    $email_message .= "First Name: ".clean_string($first_name)."\n"; 

    $email_message .= "Last Name: ".clean_string($last_name)."\n"; 

    $email_message .= "Email: ".clean_string($email)."\n"; 

    $email_message .= "Services: ".clean_string(implode(', ', $service))."\n"; 

    $email_message .= "Overview: ".clean_string($overview)."\n"; 





// create email headers 

$headers = 'From: '.$email_from."\r\n". 

'Reply-To: '.$email_from."\r\n" . 

'X-Mailer: PHP/' . phpversion(); 

@mail($email_to, $email_subject, $email_message, $headers); 

?> 



<!-- Success HTML --> 

Thank you for contacting us. We will be in touch with you very soon. 

<?php 

} 

?> 

現在，每當我執行代碼時，我得到這個錯誤： 在第48行調用未定義的函數test_input（），它是整個驗證過程的名字字段中的test_input（）。

如何解決此錯誤？

在此先感謝。

我解決了上述錯誤使用來自larsAnders的建議！感謝那！

根據我使用的新代碼，我更新了主代碼。

但是我有兩個新錯誤，對於新錯誤，我沒有收到我的電子郵件中的任何內容，我檢查了複選框，還收到電子郵件時，我沒有收到我從誰那裏得到的信息。這是我使用的HTML代碼：

<label for="service">Services required<br></label> 
<input type="checkbox" name="service[]" value="web_design_services">Web Design Services</label><br> 
<input type="checkbox" name="service[]" value="web_development_services">Web Development Services</label><br> 
<input type="checkbox" name="service[]" value="web_identity_management_services">Web Identity Management Services</label><br> 
<input type="checkbox" name="service[]" value="digital_design_services">Digital Design Services</label><br> 
<input type="checkbox" name="service[]" value="web_video_services">Web Video Services</label><br> 
<input type="checkbox" name="service[]" value="web_audio_services">Web Audio Services</label><br> 
<input type="checkbox" name="service[]" value="content_management_services">Content Management Services</label><br> 

和，這是PHP代碼的唯一行我使用關於在腳本的整個新的錯誤：

$email_message .= "Services: ".clean_string(implode(', ', $service))."\n"; 

也請告訴我在哪裏在我的電子郵件中，我沒有收到發件人。在我之前的所有腳本中，它用來顯示發件人爲「我」。

Answer 1

在PHP中，與許多語言一樣，事物的順序很重要。所以，當你的腳本正在執行，並且它到達一個函數調用時，該函數必須已經在某個地方被定義。首先，定義一個函數。然後，調用該函數。你不能在任何地方放置一個函數（比如在一個if塊中），並期望代碼搜索並使用它。確保你的函數全部在任何if塊之外定義，因爲如果條件計算結果爲false，函數將永遠不會被定義。在學習時，只需將所有功能放在腳本的頂部，而不是在任何邏輯塊之外。啓動腳本是這樣的：

function test_input($data){ 

    $data = trim($data); 
    $data = stripslashes($data); 
    $data = htmlspecialchars($data); 

    return $data; 
} 

function clean_string($string) { 

    $bad = array("content-type","bcc:","to:","cc:","href"); 
    return str_replace($bad,"",$string); 

} 

// define variables and set to empty values 
$first_nameErr = $last_nameErr = $emailErr = $overviewErr = ""; 
$first_name = $last_name = $email = $overview = ""; 

if(isset($_POST['email'])) { 

// EDIT THE 2 LINES BELOW AS REQUIRED 

$email_to = "sriprabhav@ymail.com"; 
$email_from = $_POST['email']; 

$email_subject = "Contact us - Origin web designers"; 
//{ why are there stray brackets everywhere? if(condition){code} else{code} 

if (empty($_POST["first_name"])) 
    {$first_nameErr = "(First Name is required)";} 
else 
    {$first_name = test_input($_POST["first_name"]);} 

    // check if name only contains letters and whitespace 
    if (!preg_match("/^[a-zA-Z ]*$/",$first_name)) 
{ 
    $first_name = "(Only letters and white space allowed)"; 
} 

if (empty($_POST["last_name"])) 

等......像以前一樣......

爲了處理複選框，你需要這樣的事情。這將定義一個數組名爲$服務：

if (isset($_POST['service'])) { 
    $service = $_POST['service']; 
} 

而且它可以在此行前右側放置：

//Email & SEND INFO 

然後，當你的代碼打$ email_message =「服務：行，它將有一個名爲$ service的數組來內爆。