從SQL表

Question

得到的數據我有這四列的SQL Server表：

ID, TCname, Status, Date 

我存儲在該表中的測試用例名稱和狀態和日期。我想從下面的表格中獲取數據。

1. 沒有新的測試案例加入今天（測試用例不存在，但昨天今天在座）
2. 測試用例失敗，但昨天今天通過。
3. 相同測試用例昨天和今天失敗。

感謝

Answer 1

假設你只在表中插入新記錄，而不是更新舊的。

第一個例子：

SELECT COUNT(ID) FROM [TABLE_NAME] WHERE Date >= DATEADD(dd, DATEDIFF(dd,0,GETDATE()), 0) 

第二個例子：

SELECT ID, TCName, Status, Date 
    FROM [TABLE_NAME] 
WHERE TCname IN (SELECT TCname 
        FROM [TABLE_NAME] 
        WHERE Date >= DATEADD(dd, DATEDIFF(dd,1,GETDATE()), 0) 
        AND Date <= DATEADD(dd, DATEDIFF(dd,0,GETDATE()), 0) 
        AND Status = 'Fail' 
       ) 
    AND Status = 'Pass'` 

第三示例：

SELECT ID, TCName, Status, Date 
    FROM [TABLE_NAME] 
WHERE TCname IN (SELECT TCname 
        FROM [TABLE_NAME] 
        WHERE Date >= DATEADD(dd, DATEDIFF(dd,1,GETDATE()), 0) 
        AND Date <= DATEADD(dd, DATEDIFF(dd,0,GETDATE()), 0) 
        AND Status = 'Fail' 
       ) 
    AND Status = 'Fail'` 

Answer 2

假設Date列的類型是DATE（未DATETIME），並且每每天爲每個t插入一條記錄EST情況下（即存在的那一天，很明顯）

這裏是一個小提琴，所以你可以驗證它的工作原理是，你需要：http://sqlfiddle.com/#!6/1c627/5

SELECT COUNT(*) FROM cases c WHERE NOT EXISTS(SELECT 1 FROM cases sub_c 
WHERE sub_c.TCname = c.TCname 
AND sub_c.Date <= DATEADD(day,DATEDIFF(day, 1, GETDATE()), 0)) 

SELECT TCname FROM cases c WHERE EXISTS(SELECT 1 FROM cases sub_c 
WHERE sub_c.TCname = c.TCname 
AND sub_c.Date = DATEADD(day,DATEDIFF(day, 0, GETDATE()), 0) 
AND sub_c.Status = 'PASS') 
AND EXISTS(SELECT 1 FROM cases sub_c 
WHERE sub_c.TCname = c.TCname 
AND sub_c.Date = DATEADD(day,DATEDIFF(day, 1, GETDATE()), 0) 
AND sub_c.Status = 'FAIL') 
GROUP BY c.TCname 

SELECT TCname FROM cases c WHERE EXISTS(SELECT 1 FROM cases sub_c 
WHERE sub_c.TCname = c.TCname 
AND sub_c.Date = DATEADD(day,DATEDIFF(day, 0, GETDATE()), 0) 
AND sub_c.Status = 'FAIL') 
AND EXISTS(SELECT 1 FROM cases sub_c 
WHERE sub_c.TCname = c.TCname 
AND sub_c.Date = DATEADD(day,DATEDIFF(day, 1, GETDATE()), 0) 
AND sub_c.Status = 'FAIL') 
GROUP BY c.TCname 

Answer 3

假設你的日期欄是DATETIME

1.今天沒有新增測試用例

SELECT COUNT (*) AS [New Test Case Count] 
FROM Testcase 
WHERE DATE >= DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE())) 

2.測試例昨天失敗但通過今天

SELECT DISTINCT TCname 
FROM Testcase 
WHERE TCName IN (SELECT TCName 
       FROM Testcase t 
       WHERE Date BETWEEN DATEADD(dd, 0, DATEDIFF(dd, 1, GETDATE())) 
           AND DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE())) 
       AND t.Status = 'FAIL') 
AND DATE >= DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE())) 
AND Status = 'PASS' 

3.測試案例昨天和今天都失敗了。 SQL Fiddle Demo

SELECT DISTINCT TCname 
FROM Testcase 
WHERE TCName IN (SELECT TCName 
       FROM Testcase t 
       WHERE t.Date >= DATEADD(dd, 0, DATEDIFF(dd, 1, GETDATE())) 
       AND t.Date < DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE())) 
       AND t.Status = 'FAIL') 
AND DATE >= DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE())) 
AND Status = 'FAIL'