ios-issue與sqlite數據庫路徑

-1

這是我的代碼：它適用於其他方法，但僅在此創建問題。在這裏，我無法插入數據... 這裏有什麼問題？代碼工作得很好。ios-issue與sqlite數據庫路徑

-(void) insertleadership { 
[self trunleadership]; 
// Setup the database object 
sqlite3 *database; 
NSLog(@"Inside leadership"); 
if(sqlite3_open([databasePath UTF8String], &database) == SQLITE_OK) { 
    // Setup the SQL Statement and compile it for faster access 
    // NSString *query=[stringWithFormat: @"select name,password from customer where name=%@ and password=%@",*login_name,*login_pass]; 
    sqlite3_stmt *compiledStatement; 
    for(int i=0;i&lt;ltitle.count;i++) 
    { 
     // NSString *insertSQL = [NSString stringWithFormat:@"insert into category values(\'aa\',\'bb\',\'cc\',\'cc\',\'cc\')"]; 
     // NSLog(@"Inside leadership"); 
     NSString *insertSQL = [NSString stringWithFormat:@"insert into leadership values(\'%@\',\'%@\',\'%@\',\'%@\',\'%@\',\'%@\',\'%@\',\'%@\',\'%@\',\'%@\',\'%@\',\'%@\',\'%@\')",[ltitle objectAtIndex:i],[ldate objectAtIndex:i],[lfunction objectAtIndex:i],[lservice objectAtIndex:i],[lsubservice objectAtIndex:i],[labstract objectAtIndex:i],[ldoctype objectAtIndex:i],[lcreated objectAtIndex:i],[lcorridor objectAtIndex:i],[lfeature objectAtIndex:i],[lindiastory objectAtIndex:i],[lpublish objectAtIndex:i],[ltopic objectAtIndex:i]]; 
     // NSLog(@"SQL Query for leader:%@",insertSQL); 
     const char *insert_stmt = [insertSQL UTF8String]; 
     // sqlite3_prepare_v2(databaseName, insert_stmt, -1, &statement, NULL); 
     sqlite3_prepare_v2(database, insert_stmt, -1, &compiledStatement, NULL); 
     if(sqlite3_step(compiledStatement) == SQLITE_DONE){ 
      NSLog(@"Insert into leadership successful"); 
     } 
     else { 
      NSLog(@"Unable to insert in leadership"); 
     } 
     // Release the compiled statement from memory 
     sqlite3_finalize(compiledStatement); 
    } 
    sqlite3_close(database); 
    } 
}

來源

2013-01-22 preetam

幾乎可以肯定你的「databasePath」是指包中的數據庫。該軟件包是隻讀的，在使用之前必須複製DB文件以讀/寫空間。 –

如果你添加一些報告，以你的代碼，源碼本身會告訴你爲什麼它不開放：

if(sqlite3_open([databasePath UTF8String], &database) == SQLITE_OK) 
{ 
    // Do something 
    splite3_close(database); 
} 
else 
{ 
    NSLog(@"Failed to open database '%@': %s", databasePath, sqlite3_errmsg(database)); 
}

而且@HotLicks是正確的，你應該複製數據庫退出應用除非您只讀（通過使用sqlite3_open_v2()並將SQLITE_OPEN_READONLY作爲其中一個標誌）打開它。

來源

2013-01-22 13:43:17 trojanfoe

ios-issue與sqlite數據庫路徑

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