操作數應該包含1列 - MySQL的NOT IN

SELECT * from campaigns WHERE id not in 
(SELECT 
    e.id_campaign, d.name, d.frequency, d.country, d.referral, d.bid, d.status, COUNT(e.id) AS countcap 
    FROM campaigns d 
    LEFT JOIN served e 
    ON d.id = e.id_campaign 
    WHERE 
     d.status = 'Active' 
    GROUP BY e.id_campaign 
    HAVING 
     countcap < d.frequency)

我得到的錯誤「操作數應該包含1列」 - 但我需要COUNT（e.id）操作數應該包含1列 - MySQL的NOT IN

來源

2011-06-11 reefine

我想選擇「運動」不匹配的ID匹配SELECT括號內 – reefine 2011-06-11 22:38:13

總是有這樣的：

select * 
from campaigns 
where id not in (
    select id_campaign from (
     select e.id_campaign as id_campaign, d.frequency, e.id 
     from campaigns d left join served e on d.id = e.id_campaign 
     where d.status = 'Active' 
     group by e.id_campaign 
     having count(e.id) < d.frequency 
    ) 
)

來源

2011-06-11 22:44:50

第二個子查詢是否創建第二個臨時表？沒有更好的方法嗎？ :( – 2013-04-03 19:57:09

@dudelgrincen：這取決於數據庫，通常可以使用LEFT JOIN而不是另一個子查詢，但是HAVING要求使事情變得複雜，我通常只是試圖清楚地表達邏輯並讓數據庫找出它，如果它是太慢，那麼你看數據，索引和查詢計劃，並開始調整。 – 2013-04-03 20:34:41

的 '不' 子句預計列表值。因此，如下面的查詢將工作：

SELECT * from campaigns WHERE id not in 
(SELECT 
    e.id_campaign 
    FROM campaigns d 
    LEFT JOIN served e 
    ON d.id = e.id_campaign 
    WHERE 
     d.status = 'Active' 
    GROUP BY e.id_campaign 
    HAVING 
     COUNT(e.id) < d.frequency)

如果你能告訴我們你要選擇表的結構和內容，我們就可以找出正確的查詢適合您。

來源

2011-06-11 20:13:42 Chandranshu

當我運行此查詢，我得到「未知列'的所有記錄d.frequency'in'having clause'「 – reefine 2011-06-11 22:35:13

操作數應該包含1列 - MySQL的NOT IN

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