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我目前有一個看起來像這樣的PostgreSQL表,數據列是JSON,我試圖根據可能或不可能在JSON數據中的鍵來查詢表。Postgres查詢JSON數據
| A | B | C | data |
----------------------------------------------------
| 1 | 2 | 3 | {} |
| 2 | 3 | 3 | {"name": "jack", "message": "123"} |
| 3 | 4 | 3 | {"name": "jill", "voice": "456"} |
| 4 | 2 | 3 | {"name": "bill", "email" "789"} |
目前我有
SELECT *
FROM (
SELECT
a,
b,
c,
coalesce(
CASE
WHEN (data ->> 'message') IS NULL
THEN NULL
ELSE (data ->> 'message')
END,
'') AS message,
coalesce(
CASE
WHEN (data ->> 'voice') IS NULL
THEN NULL
ELSE (data ->> 'voice')
END,
'') AS voice,
coalesce(
CASE
WHEN (data ->> 'email') IS NULL
THEN NULL
ELSE (data ->> 'email')
END,
'') AS email
FROM mytable) AS t
WHERE (t.message = "789" OR
t.voice = "789" OR
t.email = "789");
我目前得到的錯誤,錯誤:列「789」不存在
我知道有可能做的更有效的方式。任何幫助不勝感激。
字符串需要用SQL中的單引號引起來。雙引號是標識符。 –
Ahhhhhh!如此明顯。謝謝 –