使用正則表達式預浸更換

Question

我想知道最好的正則表達式替換此字符串與VID_ID它

$code = '&lt;object width=&quot;420&quot; height=&quot;345&quot;&gt;<br /> 
    &lt;param name=&quot;movie&quot; value=&quot;http://www.badoobook.com/clips/swf/player.swf&quot;&gt;&lt;/param&gt;<br /> 
    &lt;param name=&quot;allowFullScreen&quot; value=&quot;true&quot;&gt;&lt;/param&gt;&lt;param name=&quot;flashvars&quot; value=&quot;vid_id=100226&amp;MainURL=http%3A%2F%2Fwww.bado obook.com%2Fclips&amp;em=1&quot;&gt;<br /> 
    &lt;embed src=&quot;http://www.badoobook.com/clips/swf/player.swf&quot; flashvars=&quot;vid_id=100226&amp;MainURL=http%3A%2F%2Fwww. badoobook.com%2Fclips&amp;em=1&quot; type=&quot;application/x-shockwave-flash&quot; allowScriptAccess=&quot;always&quot; width=&quot;420&quot; height=&quot;345&quot; allowFullScreen=&quot;true&quot;&gt;&lt;/embed&gt;&lt;/object&gt;' 
$regular = ''; 
$code = preg_replace($regular ,'$1' , $code); 
echo $code; 

在這段代碼中的VID ID是

值= " VID_ID = &

感謝幫助

Answer 1

你可以使用正則表達式是這樣的：

(?<=vid_id=)\d+ 

這將使用positive lookbehind匹配任意數量的由文字字符集之前數字「VID_ID =」

這又是與使用RegexBuddy評論：

@" 
(?<=   # Assert that the regex below can be matched, with the match ending at this position (positive lookbehind) 
    vid_id=  # Match the characters 「vid_id=」 literally 
) 
\d   # Match a single digit 0..9 
    +    # Between one and unlimited times, as many times as possible, giving back as needed (greedy) 
" 

你已經用php和asp.net標記了你的問題，所以我不確定你在做什麼。這裏既是：

Asp.Net（C＃）

Regex.Replace(@"...uot;vid_id=100226&amp;...", @"(?<=vid_id=)\d+", "[Your value here]") 

PHP

echo preg_replace("(?<=vid_id=)\d+", "[Your value here]", "...uot;vid_id=100226&amp;..."); 

Answer 2

使用正則表達式：

vid_id=(\d+)