致命錯誤：無法使用類型mysqli_result的對象

Question

我要打開我的網站時，我發現我的MODS的人給我這個錯誤：

Fatal error: Cannot use object of type mysqli_result as array in /var/www/vbsubscribetouser.php on line 303

我就去排隊303，這是我發現：

//Check if requested username can be followed. 
if (in_array($followingdata['usergroupid'], explode("|", $vbulletin->options['subscribetouser_usergroups_cannot']))){ 

這裏開始在行303所有代碼：

//Check if requested username can be followed. 
if (in_array($followingdata['usergroupid'], explode("|", $vbulletin->options['subscribetouser_usergroups_cannot']))){ 
    exit; 
} 

if ($followinginfo[subscribers] > 0){ 
    $user_followers = $followinginfo[followers].$userinfo[userid].'|'; 
} 
else{ 
    $user_followers = '|'.$userinfo[userid].'|'; 
} 

$vbulletin->db->query_write(" 
    UPDATE " . TABLE_PREFIX . "user 
    SET subscribers = subscribers + 1, `followers` = '$user_followers' 
    WHERE userid = $followinginfo[userid] 
"); 

我不是在PHP代碼方面的專家，所以雙在打開網站之前，幫助會很好。任何幫助/建議？

非常感謝！

Answer 1

Cannot use object of type mysqli_result as array

使用mysqli_fetch_assoc或mysqli_fetch_array抓取結果一行作爲關聯陣列。

$query = "SELECT 1"; 
$result = $mysqli->query($query); 
$followingdata = $result->fetch_assoc() 

或

$followingdata = $result->fetch_array(MYSQLI_ASSOC);