SQL + PHP - 致命錯誤：無法使用類型mysqli_result作爲陣列的對象爲什麼

Question

這裏是我的代碼：

<?php 

$con = mysqli_connect("127.0.0.1:3306","root","root","photoshare"); 
$query = "SELECT ID,nickname,photoLikes FROM tbl_photo"; 
$result = mysqli_query($con,$query); 
$query_dislike = "SELECT nickname, idGivenLike FROM tbl_check_like"; 
$resultDislike = mysqli_query($con,$query_dislike); 
$photoIDdislike; 
$photoID; 
while($photoID = mysqli_fetch_assoc ($result) || $photoIDdislike = mysqli_fetch_assoc($resultDislike) ) 
{ 
//checks if both of results 
if($result["ID"] != $resultDislike["idGivenLike"]) 
{ 
echo "true"; 
} 
} 
?> 

當我運行它，它說，下一行

if($result["ID"] != $resultDislike["idGivenLike"]) 

用H致命錯誤：Fatal error: Cannot use object of type mysqli_result as array

爲什麼它不工作，我該如何解決它？

Answer 1

if($result["ID"] != $resultDislike["idGivenLike"]) 

應該是：

if($photoID["ID"] != $photoIDdislike["idGivenLike"]) 

$resultDislike/$result是你的MySQL資源，$photoID/$photoIDdislike是讀取行（陣列）。

Answer 2

應該

$photoID["ID"] != $photoIDdislike["idGivenLike"] 
// In script 
if($photoID["ID"] != $photoIDdislike["idGivenLike"]) 
{ 
    echo "true"; 
}