用逗號

Question

結合的結果和獨立的我有這個疑問：

SELECT 
    tud.detail_company_name AS company_name, 
    tud.detail_country AS company_country, 
    trv.review_title AS review_title 
FROM users_detail tud 
INNER JOIN users_auth tua 
    ON tud.user_id = tua.user_id 
LEFT JOIN reviews trv 
    ON tud.user_id = trv.review_company_id 
WHERE 
    tua.auth_user_type = "company" OR tua.auth_user_type = "guestcompany" 

查詢工作正常，並返回這樣的結果：

Array 
(
    [0] => Array 
     (
      [company_name] => The Coffee Brewery 
      [company_country] => US 
      [review_title] => 
     ) 
    [1] => Array 
     (
      [company_name] => Crea Nail Art Studio 
      [company_country] => SG 
      [review_title] => 
     ) 
    [2] => Array 
     (
      [company_name] => Hello Mall 
      [company_country] => JP 
      [review_title] => Fake goods! 
     ) 
    [3] => Array 
     (
      [company_name] => Hello Mall 
      [company_country] => JP 
      [review_title] => Never buy in there! 
     ) 
) 

正如你注意到數組鍵2 & 3具有相同company_name但不同review_title。是否有可能必須加入一個結果並用逗號分隔？例如說，這樣的結果：

Array 
(
    [0] => Array 
     (
      [company_name] => The Coffee Brewery 
      [company_country] => US 
      [review_title] => 
     ) 
    [1] => Array 
     (
      [company_name] => Crea Nail Art Studio 
      [company_country] => SG 
      [review_title] => 
     ) 
    [2] => Array 
     (
      [company_name] => Hello Mall 
      [company_country] => JP 
      [review_title] => Fake goods!, Never buy in there! 
     ) 
) 

編輯

如果反應是這樣的：

Array 
(
    [0] => Array 
     (
      [company_name] => The Coffee Brewery 
      [company_country] => US 
      [review_title] => 
      [review_approved] => 
     ) 
    [1] => Array 
     (
      [company_name] => Crea Nail Art Studio 
      [company_country] => SG 
      [review_title] => 
      [review_approved] => 
     ) 
    [2] => Array 
     (
      [company_name] => Hello Mall 
      [company_country] => JP 
      [review_title] => Fake goods! 
      [review_approved] => 1 
     ) 
    [3] => Array 
     (
      [company_name] => Hello Mall 
      [company_country] => JP 
      [review_title] => Never buy in there! 
      [review_approved] => 0 
     ) 
) 

我能不包括0的review_titleGROUP_CONCAT review_approved？所以它會輸出這樣的？

Array 
(
    [0] => Array 
     (
      [company_name] => The Coffee Brewery 
      [company_country] => US 
      [review_title] => 
     ) 
    [1] => Array 
     (
      [company_name] => Crea Nail Art Studio 
      [company_country] => SG 
      [review_title] => 
     ) 
    [2] => Array 
     (
      [company_name] => Hello Mall 
      [company_country] => JP 
      [review_title] => Fake goods! 
     ) 
) 

Answer 1

是的。使用GROUP_CONCAT()：

SELECT 
    tud.detail_company_name AS company_name, 
    tud.detail_country AS company_country, 
    GROUP_CONCAT(trv.review_title SEPARATOR ',') AS review_titles 
FROM users_detail tud 
INNER JOIN users_auth tua 
    ON tud.user_id = tua.user_id 
LEFT JOIN reviews trv 
    ON tud.user_id = trv.review_company_id 
WHERE 
    tua.auth_user_type = :company OR tua.auth_user_type = :guestcompany 
GROUP BY 
    tud.detail_company_name, 
    tud.detail_country;