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我有一個簡單的Python龍捲風Websockets服務器,接收來自JavaScript客戶端的消息。我試圖發送JSON數據,我發現的唯一解決方案是將Json對象轉換爲字符串Json,然後發送,另一方面通過服務器將字符串解析回Json。這裏是我的JSON文件:在Websockets上發送JSON
{
"events": [
{
"id": 0,
"new": {
"description": "blabla bla keyyys",
"keys": [
"keyyys",
"key "
],
"start": "2.000000",
"end": "7.000000",
"priority": "normal"
}
},
{
"id": 1,
"new": {
"description": "anything key ",
"keys": [
"keyyys",
"key "
],
"start": "0.761077",
"end": "10.026667",
"priority": "high"
}
}
]
}
之前,我把它我的另一個元素添加到JSON:
var messageValue = {};
var sendings;
messageValue["messageType"] = "mainfest";
$.getJSON("file.json", function(json) {
messageValue["data"]= json;
console.log(messageValue);
sendings = jsonToStringConvertor(messageValue);
});
var socket = new WebSocket('ws://localhost:9000/');
socket.onopen = function(event){
socket.send(sendings);
}
。 。
function jsonToStringConvertor(obj)
{
var re = JSON.stringify(obj);
return re;
}
到目前爲止好。但是當我嘗試解析返回的Json這樣
JsonFormattedMessage = json.loads(message)[0]
我得到這個錯誤:
ERROR:tornado.application:Uncaught exception in/
Traceback (most recent call last):
File "/usr/local/lib/python3.4/dist-packages/tornado/websocket.py", line 494, in _run_callback
result = callback(*args, **kwargs)
File "index.py", line 27, in on_message
JsonFormattedMessage = json.loads(message)[0]
KeyError: 0
你是什麼意思'json.loads(message)[0]'?此消息絕對是字典,但不是列表。 – Sraw