我們需要在sql server中拆分兩列數據

Question

我們需要拆分sql server中兩列的數據。

CREATE TABLE #t (Id int,Number varchar(32),Name varchar(32));  

Insert Into #t(Id, Number,Name) 
Values(123, '1,2,3','a~b~c') , 
(456, '1,2,3,4','a~b~c~d'), 
(789, '1,2','a~b') 

SELECT *FROM #t 

輸入：

Id Number Name 
123 1,2,3 a~b~c 
456 1,2,3,4 a~b~c~d 
789 1,2 a~b 

我們需要輸出以下格式：

Id Number Name 
123 1 a 
123 2 b 
123 3 c 
456 1 a 
456 2 b 
456 3 c 
456 4 d 
789 1 a 
789 2 b 

Answer 1

有了一個解析器和一個十字架援助申請

Select A.ID 
     ,B.* 
From #t A 
Cross Apply ( Select Number=C.RetVal 
         ,Name =D.RetVal 
        From (Select * from [dbo].[udf-Str-Parse](A.Number,',')) C 
        Join (Select * from [dbo].[udf-Str-Parse](A.Name,'~')) D 
        on (C.RetSeq=D.RetSeq) 
      ) B 

返回

ID Number Name 
123 1  a 
123 2  b 
123 3  c 
456 1  a 
456 2  b 
456 3  c 
456 4  d 
789 1  a 
789 2  b 

如果需要

的UDF

CREATE FUNCTION [dbo].[udf-Str-Parse] (@String varchar(max),@Delimiter varchar(10)) 
Returns Table 
As 
Return ( 
    Select RetSeq = Row_Number() over (Order By (Select null)) 
      ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)'))) 
    From (Select x = Cast('<x>'+ Replace(@String,@Delimiter,'</x><x>')+'</x>' as xml).query('.')) as A 
    Cross Apply x.nodes('x') AS B(i) 
); 

編輯，如果你不能使用UDF - 我們可以移動UDF代碼轉換成兩個子查詢產生相同的結果

Select A.ID 
     ,B.* 
From #t A 
Cross Apply ( Select Number=C.RetVal 
         ,Name =D.RetVal 
        From (
         Select RetSeq = Row_Number() over (Order By (Select null)) 
           ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)'))) 
          From (Select x = Cast('<x>'+ Replace(A.Number,',','</x><x>')+'</x>' as xml).query('.')) as A 
          Cross Apply x.nodes('x') AS B(i) 
         ) C 
        Join (
         Select RetSeq = Row_Number() over (Order By (Select null)) 
           ,RetVal = LTrim(RTrim(B.i.value('(./text())[1]', 'varchar(max)'))) 
          From (Select x = Cast('<x>'+ Replace(A.Name,'~','</x><x>')+'</x>' as xml).query('.')) as A 
          Cross Apply x.nodes('x') AS B(i) 
         ) D 
        on (C.RetSeq=D.RetSeq) 
      ) B 

Answer 2

下面是使用該方法的CTE ..

;WITH cte_1 
AS 
    (SELECT Id,ROW_NUMBER()OVER(PARTITION BY ID ORDER BY ID,LTRIM(RTRIM(m.n.value('.[1]','varchar(8000)'))))RNO 
    ,LTRIM(RTRIM(m.n.value('.[1]','varchar(8000)'))) AS Number 

    FROM 
    (
    SELECT Id 
      ,CAST('<XMLRoot><RowData>' + REPLACE(Number,',','</RowData><RowData>') + '</RowData></XMLRoot>' AS XML) AS x 
    FROM #t 
    )t 
    CROSS APPLY x.nodes('/XMLRoot/RowData')m(n)) 
,cte_2 
AS 
    (SELECT Id,ROW_NUMBER()OVER(PARTITION BY ID ORDER BY ID,LTRIM(RTRIM(m.n.value('.[1]','varchar(8000)'))))RNO 
    ,LTRIM(RTRIM(m.n.value('.[1]','varchar(8000)'))) AS Name 

    FROM 
    (
    SELECT Id,CAST('<XMLRoot><RowData>' + REPLACE(Name,'~','</RowData><RowData>') + '</RowData></XMLRoot>' AS XML) AS x 
    FROM #t 
    )t 
    CROSS APPLY x.nodes('/XMLRoot/RowData')m(n)) 
SELECT a.id,a.Number,b.name 
FROM cte_1 a JOIN cte_2 b 
    ON a.id=b.id and a.RNo=b.RNo 

Answer 3

XML和CTE的另一種方式：

DECLARE @x xml 

SELECT @x = (
    SELECT Id as '@id', 
      CAST('<n number="'+REPLACE(Number,',','"/><n number="')+'"/>' as xml), 
      CAST('<w name="'+REPLACE([Name],'~','"/><w name="')+'" />' as xml) 
    FROM #t 
    FOR XML PATH('i') 
) 

;WITH numbers AS (
SELECT t.v.value('../@id','int') as id, 
     t.v.value('@number','nvarchar(10)') as number, 
     ROW_NUMBER() OVER (PARTITION BY t.v.value('../@id','int') ORDER BY (SELECT NULL)) as RN 
FROM @x.nodes('/i/n') as t(v) 
), names AS (
SELECT t.v.value('../@id','int') as id, 
     t.v.value('@name','nvarchar(10)') as [name], 
     ROW_NUMBER() OVER (PARTITION BY t.v.value('../@id','int') ORDER BY (SELECT NULL)) as RN 
FROM @x.nodes('/i/w') as t(v) 
) 

SELECT n.id, 
     n.number, 
     nn.[name] 
FROM numbers n 
INNER JOIN names nn 
    ON n.id = nn.id and n.rn = nn.rn 

輸出：

id number name 
123 1  a 
123 2  b 
123 3  c 
456 1  a 
456 2  b 
456 3  c 
456 4  d 
789 1  a 
789 2  b 

我在ROW_NUMBER使用SELECT NULL（）部分獲得訂購的是。但它可能會導致一些問題，如不正確的訂購。