你的例子表明,你存儲使用自定義表示日期爲一個字符串 - 使用日期格式不符合。所以我們需要將日期轉換爲日期數據類型,以便能夠相應地對它們進行排序。
SQL> create table TB_DATES
2 (
3 DATE_VALUE VARCHAR2(11)
4 )
5/
Table created
SQL>
SQL> insert into tb_dates(date_value)
2 select '5th Feb 11' from dual union all
3 select '2nd Jan 11' from dual union all
4 select '6th Feb 11' from dual union all
5 select '11th Jan 11' from dual
6 ;
4 rows inserted
SQL> commit;
Commit complete
SQL> select * from tb_dates;
DATE_VALUE
-----------
5th Feb 11
2nd Jan 11
6th Feb 11
11th Jan 11
SQL> alter table tb_dates add srno number;
Table altered
QL> select * from tb_dates;
DATE_VALUE SRNO
----------- ----------
5th Feb 11 null
2nd Jan 11 null
6th Feb 11 null
11th Jan 11 null
SQL> merge into tb_dates t
2 using(
3 select rownum rn
4 , Date_value
5 , rid
6 from (select to_date(concat(lpad(dy, 2, '0'), tr), 'dd Mon yy') dt
7 , Date_value
8 , rid
9 from (select regexp_substr(substr(Date_value, 1, regexp_instr(date_value, '[[:space:]]') - 1), '[[:digit:]]+') dy
10 , substr(Date_value, regexp_instr(date_value, '[[:space:]]'), length(Date_value)) tr
11 , Date_value
12 , rowid rid
13 from tb_dates)
14 order by 1
15 )) q
16 on (q.rid = t.rowid)
17 when matched
18 then update set t.srno = q.rn
19 ;
Done
SQL> commit;
Commit complete
select * from tb_dates;
DATE_VALUE SRNO
----------- ----------
5th Feb 11 3
2nd Jan 11 1
6th Feb 11 4
11th Jan 11 2
SQL> select * from tb_dates order by srno;
DATE_VALUE SRNO
----------- ----------
2nd Jan 11 1
11th Jan 11 2
5th Feb 11 3
6th Feb 11 4
請給出一個例子(至少2-3行)你的數據是什麼樣的,你需要將它轉換成什麼樣的。顯示迄今爲止已經嘗試過的內容也會有所幫助。 – Mat
添加數據以進行說明 –
您是不是真的將您的日期存儲爲varchar,這種可怕的格式是您的嗎? –