SQL Runnnig相同的查詢多次

Question

我有一個查詢，給了我兩個日期之間的COUNT，start_date & end_date並按各個列分組。 有沒有什麼辦法可以每天得到COUNT？正如在說start_date是date1和end_date是date5，所以我需要運行查詢一次'date1到date2'，'date1到date3'，然後'date1到date4'，然後'date1到date5'。如同基於開始&結束日期多次運行相同的查詢？ 我的查詢看起來像

Select COUNT(A), B, C, D 
FROM TABLE 
WHERE CONDITION1 AND DATE BETWEEN start_date AND end_date 
GROUP BY B, C, D 

Answer 1

Select COUNT(A), B, C, D,DATE 
FROM TABLE 
WHERE CONDITION1 AND DATE BETWEEN start_date AND end_date 
GROUP BY B, C, D,DATE 

在組由

添加DATE如果該字段日期時間然後使用convert（從@ ta.speot.is：SQL Server 2005中沒有DATE作爲一種類型）

Select COUNT(A), B, C, D,convert(date,DATETime) 
    FROM TABLE 
    WHERE CONDITION1 AND DATE BETWEEN start_date AND end_date 
    GROUP BY B, C, D,convert(date,DATETime) 

在組添加DATE由

編輯基礎上，OP：

declare increment int; 
set increment = 1 
declare tempdate date; 

set tempdate = start_date 
while (tempdate < end_date) 


Select COUNT(A), B, C, D,DATE 
    FROM TABLE 
    WHERE CONDITION1 AND DATE BETWEEN start_date AND DATEADD(day,increment, start_date) 
    GROUP BY B, C, D,DATE 

set increment = increment + 1 
set tempdate = DATEADD(day,1,tempdate) 
end 

，你必須使用循環和做像一些事情上面

Answer 2

我會告訴我如何與甲骨文實現這一目標以及如何同可能適用於Vertica。

我開始寫一個查詢來獲取日期列表。就像這樣：

select to_date('01-APR-2015','dd-mon-yyyy') + rownum -1 as begin_date 
from all_objects 
where rownum <= to_date('05-APR-2015','dd-mon-yyyy') - to_date('01-APR-2015','dd-mon-yyyy')+1; 

這將返回：

01-APR-15 12:00:00 AM 
02-APR-15 12:00:00 AM 
03-APR-15 12:00:00 AM 
04-APR-15 12:00:00 AM 
05-APR-15 12:00:00 AM 

我不是太熟悉，Vertica的，但看起來這可能與此查詢來實現：

SELECT ts::DATE 
    FROM (SELECT '04/01/2015'::TIMESTAMP as tm 
     UNION 
     SELECT '04/05/2015'::TIMESTAMP as tm) as t 
TIMESERIES ts as '1 Day' OVER (ORDER BY tm); 

（來源：http://www.vertica-forums.com/viewtopic.php?t=1333）

然後，我使用笛卡爾/交叉連接到相同的查詢來創建日期運行GES：

select * 
from (
    select to_date('01-APR-2015','dd-mon-yyyy') + rownum -1 as begin_date 
    from all_objects 
    where rownum <= to_date('05-APR-2015','dd-mon-yyyy')-to_date('01-APR-2015','dd-mon-yyyy')+1 
) q1, (
    select to_date('01-APR-2015','dd-mon-yyyy') + rownum -1 as end_date 
    from all_objects 
    where rownum <= to_date('05-APR-2015','dd-mon-yyyy')-to_date('01-APR-2015','dd-mon-yyyy')+1 
) q2 
where begin_date <= end_date; 

結果是這樣的：

BEGIN_DATE    END_DATE 
01-APR-15 12:00:00 AM 01-APR-15 12:00:00 AM 
01-APR-15 12:00:00 AM 02-APR-15 12:00:00 AM 
01-APR-15 12:00:00 AM 03-APR-15 12:00:00 AM 
01-APR-15 12:00:00 AM 04-APR-15 12:00:00 AM 
01-APR-15 12:00:00 AM 05-APR-15 12:00:00 AM 
02-APR-15 12:00:00 AM 02-APR-15 12:00:00 AM 
02-APR-15 12:00:00 AM 03-APR-15 12:00:00 AM 
02-APR-15 12:00:00 AM 04-APR-15 12:00:00 AM 
02-APR-15 12:00:00 AM 05-APR-15 12:00:00 AM 
03-APR-15 12:00:00 AM 03-APR-15 12:00:00 AM 
03-APR-15 12:00:00 AM 04-APR-15 12:00:00 AM 
03-APR-15 12:00:00 AM 05-APR-15 12:00:00 AM 
04-APR-15 12:00:00 AM 04-APR-15 12:00:00 AM 
04-APR-15 12:00:00 AM 05-APR-15 12:00:00 AM 
05-APR-15 12:00:00 AM 05-APR-15 12:00:00 AM 

如果不想單日範圍（例如，2015年4月1日 - 2015年4月1日）只是改變BEGIN_DATE < = end_date to begin_date < end_date。

一旦你有，你可以加入到查詢整個查詢你正在運行：

Select q.begin_date, q.end_date, t.B, t.C, t.D, count(t.A) 
FROM tmp t, (
    select * 
    from (
     select to_date('01-APR-2015','dd-mon-yyyy') + rownum -1 as begin_date 
     from all_objects 
     where rownum <= to_date('05-APR-2015','dd-mon-yyyy')-to_date('01-APR-2015','dd-mon-yyyy')+1 
    ) q1, (
     select to_date('01-APR-2015','dd-mon-yyyy') + rownum -1 as end_date 
     from all_objects 
     where rownum <= to_date('05-APR-2015','dd-mon-yyyy')-to_date('01-APR-2015','dd-mon-yyyy')+1 
    ) q2 
    where begin_date <= end_date 
) q 
where t.theDate between q.begin_date and q.end_date 
group by q.begin_date, q.end_date, t.B, t.C, t.D 
order by q.begin_date, q.end_date; 

這裏有一個SQLFiddle：http://sqlfiddle.com/#!4/9628d/9

我希望幫助。