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我有實體如下。我如何將DataTable轉換爲列表{對象,列表{對象}} Linq
namespace Entity
{
public class MasterMenu
{
public MasterMenuParent MasterMenuParent;
public List<MasterMenuChildOfParent> MasterMenuChildOfParent;
}
public class MasterMenuParent
{
public string Id { get; set; }
public string Name { get; set; }
}
public class MasterMenuChildOfParent
{
public string Id { get; set; }
public string Name { get; set; }
public string ParentId { get; set; } //It's a foreign key that link to MasterMenuParent.Id
}
}
我查詢數據庫中的數據並轉換爲實體。 對於getDataMasterMenu1()我使用兩個循環。 對於getDataMasterMenu2()我使用了一個Loop和linq。 對於getDataMasterMenu3()我只想使用linq,但我不知道該怎麼做,這有可能嗎?
using Entity;
public partial class Test : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
List<MasterMenu> list1 = getDataMasterMenu2();
List<MasterMenu> list2 = getDataMasterMenu2();
List<MasterMenu> list3 = getDataMasterMenu3();
}
//Using two Loop
private List<MasterMenu> getDataMasterMenu1()
{
List<MasterMenu> result = new List<MasterMenu>();
List<MasterMenuChildOfParent> tempMasterMenuChildOfParent = new List<MasterMenuChildOfParent>();
DataTable dtMasterMenuParent = new DataTable(); //Assume: I already query data from database and then load to datatable that has field: ID, NAME
DataTable dtMasterMenuChild = new DataTable(); //Assume: I already query data from database and then load to datatable that has field: ID, NAME, PARENT_ID
for (int i1 = 0; i1 < dtMasterMenuParent.Rows.Count; i1++)
{
//Select Child Of Parent
DataTable dtMasterMenuChildOfParent = (from DataRow dr in dtMasterMenuChild.Rows where dr["PARENT_ID"].Equals(dtMasterMenuParent.Rows[i1]["ID"]) select dr).CopyToDataTable();
for (int i2 = 0; i2 < dtMasterMenuChildOfParent.Rows.Count; i2++)
{
tempMasterMenuChildOfParent.Add(new MasterMenuChildOfParent
{
Id = dtMasterMenuChildOfParent.Rows[i2].Field<string>("ID"),
Name = dtMasterMenuChildOfParent.Rows[i2].Field<string>("NAME"),
ParentId = dtMasterMenuChildOfParent.Rows[i2].Field<string>("PARENT_ID"),
});
}
result.Add(new MasterMenu
{
MasterMenuParent = (new MasterMenuParent
{
Id = dtMasterMenuParent.Rows[i1].Field<string>("ID"),
Name = dtMasterMenuParent.Rows[i1].Field<string>("NAME")
}),
MasterMenuChildOfParent = tempMasterMenuChildOfParent
});
}
return result;
}
//Using one Loop and linq
private List<MasterMenu> getDataMasterMenu2()
{
List<MasterMenu> result = new List<MasterMenu>();
DataTable dtMasterMenuParent = new DataTable(); //Assume: I already query data from database and then load to datatable that has field: ID, NAME
DataTable dtMasterMenuChild = new DataTable(); //Assume: I already query data from database and then load to datatable that has field: ID, NAME, PARENT_ID
for (int i1 = 0; i1 < dtMasterMenuParent.Rows.Count; i1++)
{
//Select Child Of Parent
DataTable dtMasterMenuChildOfParent = (from DataRow dr in dtMasterMenuChild.Rows where dr["PARENT_ID"].Equals(dtMasterMenuParent.Rows[i1]["ID"]) select dr).CopyToDataTable();
result.Add(new MasterMenu
{
MasterMenuParent = (new MasterMenuParent
{
Id = dtMasterMenuParent.Rows[i1].Field<string>("ID"),
Name = dtMasterMenuParent.Rows[i1].Field<string>("NAME")
}),
MasterMenuChildOfParent = dtMenuChildOfParent.AsEnumerable().Select(row =>
new MasterMenuChildOfParent
{
Id = row.Field<string>("ID"),
Name = row.Field<string>("NAME"),
ParentId = row.Field<string>("PARENT_ID")
}).ToList()
});
}
return result;
}
//Using linq
private List<MasterMenu> getDataMasterMenu3()
{
List<MasterMenu> result = new List<MasterMenu>();
DataTable dtMasterMenuParent = new DataTable(); //Assume: I already query data from database and then load to datatable that has field: ID, NAME
DataTable dtMasterMenuChild = new DataTable(); //Assume: I already query data from database and then load to datatable that has field: ID, NAME, PARENT_ID
//How can I Convert DataTable to List{Object, List{Object}} by Linq
return result;
}
}
你爲什麼不使用這個的ORM?所有這些代碼都可以用singel'dbContext.MasterMenu.Include(m => m.MasterMenuChildOfParent).ToList()'代替。通過使用DataTables,您也使用了兩倍的內存。 –
謝謝Mr.Panagiotis Kanavos。我將學習ORM。 – akkapolk
子表中有一個額外的列。所以如果你克隆父表並添加ParentID列,你可以用一個linq來完成。 – jdweng