語法錯誤FROM子句中一個MS Access

Question

我得到一個語法錯誤在FROM子句中的對話框，當我嘗試運行MS-Access 2010中的下列查詢連接對話框訪問高亮顯示（在FROM聯繫人地址後面）

我知道我需要在Access中使用多個嵌套聯接的括號，但是有人可以解釋這是如何工作的概念，除了顯示如何修復問題是？

相關方面基本表模式的s應該從SQL SELECT語句中清除。

Answer 1

我認爲這應該工作，但我缺乏測試的權限。一般語法堅持

從表 左連接（聲明）別名 上table.col = alias.col 左加入...

改變你的語句是：

FROM Contact_addresses 

    LEFT JOIN 
     (SELECT 
      Owner_Operator.CONTACT_ID, 
      Owner_Operator.FIRM_NAME 
      FROM Owner_Operator) Owner_Operator 
     ON Contact_addresses.ContactID=Owner_Operator.CONTACT_ID 

    LEFT JOIN 
     (SELECT 
      Official_Correspondent.CONTACT_ID, 
      Official_Correspondent.FIRST_NAME, 
      Official_Correspondent.LAST_NAME, 
      Official_Correspondent.SUBACCOUNT_COMPANY_NAME, 
      Official_Correspondent.PHONE_NUMBER 
      FROM Official_Correspondent) Official_Correspondent 
     ON Contact_addresses.ContactID=Official_Correspondent.CONTACT_ID 
    ; 

我添加了表別名以匹配您在聯接中調用它的內容，並刪除了違規的一組括號。

Answer 2

的問題是在開括號（（他們需要第一FROM後立即的位置下面是什麼在起作用：。

SELECT Contact_addresses.AddressID, Contact_addresses.ContactID, Contact_addresses.Address1, Contact_addresses.Address2, Contact_addresses.City, Contact_addresses.State, Contact_addresses.Zip, Owner_Operator.FIRM_NAME, Official_Correspondent.FIRST_NAME, Official_Correspondent.LAST_NAME, Official_Correspondent.SUBACCOUNT_COMPANY_NAME, Official_Correspondent.PHONE_NUMBER 
FROM ((Contact_addresses 

     LEFT JOIN 
      (SELECT 
       Owner_Operator.CONTACT_ID, 
       Owner_Operator.FIRM_NAME 
       FROM Owner_Operator) AS Owner_Operator 
      ON Contact_addresses.ContactID=Owner_Operator.CONTACT_ID 
) 
     LEFT JOIN 
      (SELECT 
       Official_Correspondent.CONTACT_ID, 
       Official_Correspondent.FIRST_NAME, 
       Official_Correspondent.LAST_NAME, 
       Official_Correspondent.SUBACCOUNT_COMPANY_NAME, 
       Official_Correspondent.PHONE_NUMBER 
       FROM Official_Correspondent) AS Official_Correspondent 
      ON Contact_addresses.ContactID=Official_Correspondent.CONTACT_ID 
)   
;