2

我有一個PHP變量如何請求Google Place API返回地點的ID?

$location = 'London'; 

我也有谷歌地圖API第3版的JavaScript來顯示我的地圖,並放置在一個地方ID標記

var request = { 
    placeId: 'ChIJN1t_tDeuEmsRUsoyG83frY4' 
}; 

我的目標是讓我的腳本請求把我的ID PHP變量和打印ID爲我的標記位置,就像這樣:

var request = { 
    placeID: '<?=$_locationID;?>' 
}; 

如何傳遞$ locati的地方ID作爲$ _locationID的值?

回答

0
$data = "https://maps.googleapis.com/maps/api/place/textsearch/xml?query=".$location."&key=YOUR_KEY_HERE"; 

$xml = file_get_contents($data); 
$xml = simplexml_load_string($xml); 

foreach($xml->result->place_id as $key => $value){ 
    $location_id = $value; 
} 

有了這個代碼,我已經回到了正確的ID爲每個位置,在這種情況下我的$ location =「倫敦」

隨着地圖的JavaScript最後的結果是

enter image description here

1

您可以通過使用文本搜索做到這一點: -

當你搜索「倫敦」
function geoPlaceID($location){ 
    $locationclean = str_replace (" ", "+", $location); 
    $details_url = "https://maps.googleapis.com/maps/api/place/textsearch/json?query=" . $locationclean . "&key=YOUR_API_KEY"; 
    $du = file_get_contents($details_url); 
    $getDetails = json_decode(utf8_encode($du),true); 
    if ($getDetails['status']=="OK"){ 
     return $getDetails['results'][0]['place_id']; 
    } 
    else{ 
     return "Place ID not found"; 
    } 
} 

查詢結果中包含1分以上的結果:

{ 
    "html_attributions" : [], 
    "results" : [ 
     { 
     "formatted_address" : "London, UK", 
     "geometry" : { 
      "location" : { 
       "lat" : 51.5073509, 
       "lng" : -0.1277583 
      }, 
      "viewport" : { 
       "northeast" : { 
        "lat" : 51.6723432, 
        "lng" : 0.148271 
       }, 
       "southwest" : { 
        "lat" : 51.38494009999999, 
        "lng" : -0.3514683 
       } 
      } 
     }, 
     "icon" : "http://maps.gstatic.com/mapfiles/place_api/icons/geocode-71.png", 
     "id" : "b1a8b96daab5065cf4a08f953e577c34cdf769c0", 
     "name" : "London", 
     "place_id" : "ChIJdd4hrwug2EcRmSrV3Vo6llI", 
     "reference" : "CoQBdgAAAEaMNGBLSJDQzPro1sZAjnWPObrVhKk_U0-oQ9HDOhJG5Z0gUd6ZfkuvhIXOeNhs7KFRMC84dGTj_mLaXC9tXhZtluPztMwUFOTg99vDXpsccnh4iyhrYfJBZNMNOSzrLOUdXAfnBTb18EclrhWBmAbKQ8aLzJEtZyQOqc3i3FEYEhAGxbUwRj6GFekMSU19_8NaGhS03o6gl1eWpWdx5AmiKJ-oMKTRuQ", 
     "types" : [ "locality", "political" ] 
     }, 
     { 
     "formatted_address" : "London, ON, Canada", 
     "geometry" : { 
      "location" : { 
       "lat" : 42.9869502, 
       "lng" : -81.243177 
      }, 
      "viewport" : { 
       "northeast" : { 
        "lat" : 43.073245, 
        "lng" : -81.1063879 
       }, 
       "southwest" : { 
        "lat" : 42.824517, 
        "lng" : -81.390852 
       } 
      } 
     }, 
     "icon" : "http://maps.gstatic.com/mapfiles/place_api/icons/geocode-71.png", 
     "id" : "fab6815aadba41e81aa7bd51a445c4924317ec88", 
     "name" : "London", 
     "place_id" : "ChIJC5uNqA7yLogRlWsFmmnXxyg", 
     "reference" : "CoQBfgAAANqxMzFC52IV0GIn-ORiCKA5gKmt0L-CPyQJLC18UNjggnHMy0HkRN_BK5ylwViFGt_u6KsEKu9ZnhGySBrkDOdZdsFDHRJQezW1uQrBs9jc8zNF8QxlHuKh2CvncuNQbqM1kfqtpa0WXA6__0zarFTiaWff1SAJY-v4Ix9vaK0JEhCtT-q0QzngXMnALyPbp7qSGhSlejUY7ilJRTG4SfpeNRrKzZYksQ", 
     "types" : [ "locality", "political" ] 
     }, 
     { 
     "formatted_address" : "London, KY, USA", 
     "geometry" : { 
      "location" : { 
       "lat" : 37.1289771, 
       "lng" : -84.08326459999999 
      }, 
      "viewport" : { 
       "northeast" : { 
        "lat" : 37.1522599, 
        "lng" : -84.03595709999999 
       }, 
       "southwest" : { 
        "lat" : 37.0797589, 
        "lng" : -84.126262 
       } 
      } 
     }, 
     "icon" : "http://maps.gstatic.com/mapfiles/place_api/icons/geocode-71.png", 
     "id" : "692adb38e4db9759599d6f73f300a3bba7db714a", 
     "name" : "London", 
     "place_id" : "ChIJA8c2lxTNXIgRmMwHc-RRGWI", 
     "reference" : "CoQBewAAAOQz_2KNfQsQ7ph5U5cUQKjAka2ckTsdzNhyvChJKeep9MRnv4Si4mo4xBHnNtC44-mToEuALwktcuQaoevRj-AVbBX6rvwUQHkY9KuiomTgocq1uBriE0FNk1m8PEhsOHFbVxpGB61tTL-aC7NLGyix-gpBk90wfvFL6WnMtEGbEhAn2hYFbt2MymyoD56sbNEJGhTZEFCIBDTbYIY4_LTbEXtb823GYg", 
     "types" : [ "locality", "political" ] 
     } 
    ], 
    "status" : "OK" 
} 

因此,如果您搜索的名字最好是正確的地方,如果你使用的是谷歌地圖用於該地方的名稱,那麼只會有一個結果。例如:當您搜索「倫敦,英國」它會給結果只有一個:

{ 
    "html_attributions" : [], 
    "results" : [ 
     { 
     "formatted_address" : "London, UK", 
     "geometry" : { 
      "location" : { 
       "lat" : 51.5073509, 
       "lng" : -0.1277583 
      }, 
      "viewport" : { 
       "northeast" : { 
        "lat" : 51.6723432, 
        "lng" : 0.148271 
       }, 
       "southwest" : { 
        "lat" : 51.38494009999999, 
        "lng" : -0.3514683 
       } 
      } 
     }, 
     "icon" : "http://maps.gstatic.com/mapfiles/place_api/icons/geocode-71.png", 
     "id" : "b1a8b96daab5065cf4a08f953e577c34cdf769c0", 
     "name" : "London", 
     "place_id" : "ChIJdd4hrwug2EcRmSrV3Vo6llI", 
     "reference" : "CoQBdQAAAB9gHd2srTAOUumLaGYrpjppDaNOVEqRrMa58s9SADNLRXGPzLyEgLQ17zOuhJXa3ygKO-14zz6zKxNCwO24MS5zvP60EviITZlvou6exZBlIapBPcZNsFYHWlw7wTzYaj4jWqj1eZPO6FZJ2eyYeKCldZfQVT_4sMWAXmIdxklDEhCOnCuvdUriA6kyIjN4HJ6RGhQnnkzVDVFCui_lEGziSfPKmY1T7g", 
     "types" : [ "locality", "political" ] 
     } 
    ], 
    "status" : "OK" 
} 
+0

我發現它更容易通過XML請求,並使用PHP的SimpleXML函數解析。 – zak

+0

喲可以做到這一點。對不起,最初你的問題感到困惑,我以爲你有地方ID,是的感謝關於PHP的參考。在php中已經有一段時間了。無論如何,你仍然需要小心一點,就是所有地方的名字。很高興知道你能解決問題。 –

相關問題