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大家好,我試圖讓用戶在提交數據後編輯它們的數據。我有一個員工表設置了一個自動遞增的主鍵。這是我的代碼的這一點,這讓我很費心//getting id from url $StaffID = $_GET['StaffID'];
我不能爲我的生活弄清楚它有什麼問題,因爲語法似乎是正確的。這是告訴我索引是未知的。無法編輯MySQL行
<?php
// including the database connection file
include_once("connect.php");
if(isset($_POST['update']))
{
$StaffID = $_POST['StaffID'];
// checking empty fields
if(empty($Name) || empty($Address) || empty($Telephone) || empty($BusinessID)) {
if(empty($Name)) {
echo "<font color='red'>Name field is empty.</font><br/>";
}
if(empty($Address)) {
echo "<font color='red'>Age field is empty.</font><br/>";
}
if(empty($Telephone)) {
echo "<font color='red'>Email field is empty.</font><br/>";
}
if(empty($BusinessID)){
echo "<font color='red'>Email field is empty.</font><br>/";
}
} else {
//updating the table
$result = mysqli_query($conn, "UPDATE staff SET Name='$Name',Address='$Address',Telephone='$Telephone', BusinessID='$BusinessID' WHERE StaffID = $StaffID");
//redirectig to the display page. In our case, it is index.php
header("Location: HomePHP.php");
}
}
?>
<?php
//getting id from url
$StaffID = $_GET['StaffID']; // <---- ERROR
//selecting data associated with this particular id
$result = mysqli_query($conn, "SELECT * FROM staff WHERE StaffID=$StaffID");
while($res = mysqli_fetch_array($result))
{
$Name = $res['Name'];
$Address = $res['Address'];
$Telephone = $res['Telephone'];
$BusinessID = $res['BusinessID'];
}
?>
Thankyou的答覆。在更新部分,我是否保留'?'你會在哪裏放置建議的代碼位? –
是的,你保留'?','?'與下一行中的變量綁定在一起。只需將它替換爲你的代碼行「$ result = mysqli_query($ conn,」UPDATE staff ...「) – Kevin
Thankyou非常感謝你的幫助,我正在學習很多東西,但不幸的是,它給我一個Unidentified index error //從網址獲取ID $ StaffID = $ _GET ['StaffID']; –