如何計算工作日數？

我在SQL Server 2008中的表如下數據：如何計算工作日數？

user ,number of request, date number of request 

user1, ID1139151, 2017-03-15 13:10:01.000 

user1, ID1139152, 2017-03-13 14:31:05.000 

user2, ID1139153, 2017-03-16 10:38:08.000 

user2, ID1139154, 2017-03-16 09:26:04.000 

user2, ID1139155, 2017-03-17 18:09:15.000 

user2, ID1139156, 2017-03-17 20:14:29.000 

user2, ID1139157, 2017-03-28 11:18:18.000

幫我用SQL查詢的幫助每一位用戶發現天的SUMM。

Result: 

user, date number of request 

user1, 2 

user2, 3

腳本來創建數據：

CREATE TABLE Mytable (

    [user] varchar(50) NOT NULL, 

    [number of request] varchar(15) NOT NULL, 

    [date_number_of_request] datetime NOT NULL, ) 


INSERT INTO Mytable 

VALUES 

('user1','ID1139151','2017-03-15 13:10:01.000'), 

('user1','ID1139152','2017-03-13 14:31:05.000'), 

('user2','ID1139153','2017-03-16 10:38:08.000'), 

('user2','ID1139154','2017-03-16 09:26:04.000'), 

('user2','ID1139155','2017-03-17 18:09:15.000'), 

('user2','ID1139156','2017-03-17 20:14:29.000'), 

('user2','ID1139157','2017-03-28 11:18:18.000');

來源

2017-04-05 AleksTr

加1的樣本數據，前進嘗試包括你已經嘗試以及 – TheGameiswar

一種方法的任何企圖是添加[日曆表（http://www.sqlservercentral.com/blogs/dwainsql/ 2014/03/30/calendar-tables-in-t-sql /）到你的數據庫。這可以用來過濾非工作日。銀行假期不能被識別，除非你將它們存儲在某個地方。 –

使用count(distinct col)和截斷日期時間更新與dateadd(day,datediff(day, 0, [date_number_of_request]), 0)：

select [user] 
    , DaysWithRequests = count(distinct 
     dateadd(day,datediff(day, 0, [date_number_of_request]), 0) 
     ) 
from mytable 
group by [user]

相同的查詢使用convert(date,[date_number_of_request])

select [user] 
    , DaysWithRequests = count(distinct convert(date,[date_number_of_request])) 
from mytable 
group by [user]

rextester演示：http://rextester.com/EMKMK22273

回報：

+-------+------------------+ 
| user | DaysWithRequests | 
+-------+------------------+ 
| user1 |    2 | 
| user2 |    3 | 
+-------+------------------+

來源

2017-04-05 13:15:34 SqlZim

也許做這樣的事情：

SELECT users, COUNT(DISTINCT CAST(date_number_of_request AS date)) 
FROM mytable 
GROUP BY users

來源

2017-04-05 13:16:59 VDK

看樣子你想要的，爲每個用戶的不同數量的計數date_number_of_request列中的日期？

select user, count(distinct convert(date, date_number_of_request)) 
    from myTable 
group by user

來源

2017-04-05 13:17:02

如何計算工作日數？

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