0
當我研究觀察者設計模式的一個很好的例子時,我偶然發現了這段代碼。主要是,它得到錯誤,並採取暫時的[-fpermissive]的地址,我不明白它是坦率的。將類參考發送給函數?這是真實生活嗎?可以將類引用作爲參數發送給函數嗎?
#include <vector>
#include <iostream>
using namespace std;
class AlarmListener
{
public:
virtual void alarm() = 0;
};
class SensorSystem
{
vector < AlarmListener * > listeners;
public:
void attach(AlarmListener *al)
{
listeners.push_back(al);
}
void soundTheAlarm()
{
for (int i = 0; i < listeners.size(); i++)
listeners[i]->alarm();
}
};
class Lighting: public AlarmListener
{
public:
/*virtual*/void alarm()
{
cout << "lights up" << '\n';
}
};
class Gates: public AlarmListener
{
public:
/*virtual*/void alarm()
{
cout << "gates close" << '\n';
}
};
class CheckList
{
virtual void localize()
{
cout << " establish a perimeter" << '\n';
}
virtual void isolate()
{
cout << " isolate the grid" << '\n';
}
virtual void identify()
{
cout << " identify the source" << '\n';
}
public:
void byTheNumbers()
{
// Template Method design pattern
localize();
isolate();
identify();
}
};
// class inheri. // type inheritance
class Surveillance: public CheckList, public AlarmListener
{
/*virtual*/void isolate()
{
cout << " train the cameras" << '\n';
}
public:
/*virtual*/void alarm()
{
cout << "Surveillance - by the numbers:" << '\n';
byTheNumbers();
}
};
int main()
{
SensorSystem ss;
ss.attach(&Gates());
ss.attach(&Lighting());
ss.attach(&Surveillance());
ss.soundTheAlarm();
}
如果您使用的參考?我看到的一切都是使用指針。 – NathanOliver