使用bash shell的浮點在UNIX

Question

請幫我找出這個問題，我是很新的UNIX， 我的代碼是真的不能得到正確的答案...

#! /usr/bin/env bash 

echo -n "How many number : "; read num 
for ((i=0; i<$num; i++)); 
do 
    echo -n "Enter your number : "; read number 
total+=$(echo "${number}" | bc) 
echo "${total}" 

done 

Answer 1

echo -n "Enter your numbers: " 
read numbers 
total=$(echo "$numbers" | sed 's/ \+/ + /g' | bc) 
echo "The total is $total" 

示例使用：

Enter your numbers: 4 6 2.47 
The total is 12.47 

更多：在腳本中，這個問題是行total+=$(echo "${number}" | bc)。這解決了它：

#! /usr/bin/env bash 
total=0 
echo -n "How many number : "; read num 
for ((i=0; i<$num; i++)); 
do 
    echo -n "Enter your number : "; read number 
    total=$(echo "$total + ${number}" | bc) 
    echo "${total}" 
done