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我有一個NOTIFICATION
表誰包含一個多對多的關聯:JPA多對多堅持
@Entity
@Table(name="NOTIFICATION")
@NamedQuery(name="Notification.findAll", query="SELECT f FROM Notification f")
public class Notification {
/** SOME COLUMN DEFINITION NOT IMPORTANT FOR MY CASE
COD, DATE, ID_THEME, ID_TYP, IC_ARCH, ID_CLIENT, INFOS, NAME, TITRE_NOT, ID_NOT
**/
@ManyToMany
@JoinTable(
name="PJ_PAR_NOTIF"
, joinColumns={
@JoinColumn(name="ID_NOTIF")
}
, inverseJoinColumns={
@JoinColumn(name="ID_PJ_GEN")
}
)
private List<PiecesJointesGen> piecesJointesGens;
}
所以,我有一個關聯表稱爲PJ_PAR_NOTIF
。
我試圖堅持一個Notification
實體。這裏是來自Value Object的piecesJointesGens初始化:
@PersistenceContext(unitName="pu/middle")
private EntityManager entityMgr;
FoaNotification lFoaNotification = new FoaNotification();
for(PieceJointeGenVO lPJGenVO : pNotificationVO.getPiecesJointes()){
PiecesJointesGen lPiecesJointesGen = new PiecesJointesGen();
lPiecesJointesGen.setLienPjGen(lPJGenVO.getLienPieceJointeGen());
lPiecesJointesGen.setIdPjGen(lPJGenVO.getIdPieceJointeGen());
lNotification.getFoaPiecesJointesGens().add(lFoaPiecesJointesGen);
}
entityMgr.persist(pNotification);
堅持不起作用。 JPA爲我的通知對象的第一插入,這是確定:
insert
into
NOTIFICATION
(COD, DATE, ID_THEME, ID_TYP, IC_ARCH, ID_CLIENT, INFOS, NAME, TITRE_NOT, ID_NOT)
values
(?, ?, ?, ?, ?, ?, ?, ?, ?, ?)
然後,JPA嘗試在我的關聯表中插入值,但piecesJointesGen不存在的時刻:
insert
into
PJ_PAR_NOTIF
(ID_NOTIF, ID_PJ_GEN)
values
(?, ?)
所以,我有這樣的錯誤:
GRAVE: EJB Exception: : java.lang.IllegalStateException: org.hibernate.TransientObjectException: object references an unsaved transient instance - save the transient instance before flushing: com.entities.PiecesJointesGen
有沒有辦法告訴JPA的PJ_PAR_NOTIF
插入之前,插入piecesJointesGen
?
嘗試在'piecesJointesGens'映射中使用'@ManyToMany(cascade = CascadeType.PERSIST)'。 –
這就是它!謝謝@PredragMaric! – user3469203
太棒了,我已經添加了它作爲答案,因爲它幫助。 –