查找Access 2003中兩個查詢的結果之間的差異

Question

我想在Access 2003中創建一個查詢，該查詢結合了兩個查詢來查找結果之間的差異。

查詢1：[全部]

SELECT mars.Name, mars.Location, mars.Business_Unit 
FROM mars 
GROUP BY mars.Name, mars.Location, mars.Business_Unit; 

返回

Name Location Business Unit 
----- --------- ------------- 
John Sydney  AU 
Grace Brisbane AU 
Lee Melbourne GU 

問題2：[not_zero]

SELECT mars.Name, mars.Location, mars.Business_Unit 
FROM mars 
WHERE ((mars.orc)<>0) 
GROUP BY mars.Name, mars.Location, mars.Business_Unit; 

它返回：

Name Location Business Unit 
----- -------- ------------- 
John Sydney AU 
Grace Brisbane AU 

我詢問，我想創建：

SELECT m.Name, m.Location, m.Business_Unit 
FROM 
    all AS m 
    LEFT JOIN 
    Not_Zero AS o 
     ON (m.Name=o.Name) 
      AND (m.Location=o.Location) 
      AND (m.Business_Unit=o.Business_Unit) 
GROUP BY m.Name, m.Location, m.Business_Unit; 

我想我的查詢來實現：

Name Location Business Unit 
---- --------- ------------- 
Lee Melbourne GU 

而是我得到了相同的結果[全部]查詢：

Name Location Business Unit 
----- --------- ------------- 
John Sydney  AU 
Grace Brisbane AU 
Lee Melbourne GU 

好了，所以這個[火星]表是這樣的：

Name Location Business Unit ORC 
----- --------- ------------- --- 
John Sydney  AU    0 
Grace Brisbane AU    5 
John Sydney  AU    10 
Grace Brisbane AU    0 
Lee Melbourne GU    0 
Lee Paris  EU    0 

我想要做到的，是讓名字有獸人= 0一路即這就是爲什麼我想例如：

Name Location Business Unit ORC 
---- --------- ------------- --- 
Lee Melbourne GU    0 
Lee Paris  EU    0 

Answer 1

由於[not_zero]查詢結果將永遠是一個[all]查詢結果的子集，兩者之間的「差異」是[all]中不出現在[not_zero]中的行。以下查詢找到它們：

SELECT all.* 
FROM 
    all 
    LEFT JOIN 
    not_zero 
     ON (all.NAME=not_zero.NAME) 
      AND (all.LOCATION=not_zero.LOCATION) 
      AND (all.[BUSINESS UNIT]=not_zero.[BUSINESS UNIT]) 
WHERE 
    (not_zero.NAME Is Null) 
     AND (not_zero.LOCATION Is Null) 
     AND (not_zero.[BUSINESS UNIT] Is Null);