如何在oracle sql中獲取小時和分鐘？

Question

我想和顯示日期，小時和分鐘分開（3列：日期，小時和分鐘）

我的腳本不起作用。如何解決這個問題？謝謝

這裏的SQL：

select trunc(t.create_time, 'DD') as createdate 
      ,trunc(t.close_time, 'DD') as closedate 
      ,datepart(hour, t.close_time()) as hours 
      ,datepart(minute, t.close_time()) as minutes 
      ,count(t.close_time) as total 
     from app_account.otrs_ticket t 
     left join app_account.otrs_user u 
     on t.create_user_id=u.id 
     where u.id not in (15,7,31,49,50,52,62,66,69,106,17,24,44,32,33,55,22,29,30,47,45,53,70,74,109,1,2,10,23,68,80,20,21,56,108,67) 
     group by trunc(t.create_time, 'DD') 
       ,trunc(t.close_time, 'DD') 
       ,datepart(hour, t.close_time()) 
       ,datepart(minute, t.close_time()) 
     order by trunc(t.create_time, 'DD') desc 

Answer 1

我發現to_char()函數是轉換和提取日期部分最靈活的函數。

這裏是提取自SYSDATE的各種元素的例子：

select to_char(sysdate, 'YYYY') as year, 
     to_char(sysdate, 'MM') as month, 
     to_char(sysdate, 'DD') as day, 
     to_char(sysdate, 'HH24') as hour, 
     to_char(sysdate, 'MI') as minute 
from dual 

您可以提供不同格式的參數，以獲得任何結果，您需要。

Answer 2

Oracle的功能extract()或to_char()：

select trunc(t.create_time, 'DD') as createdate, 
     trunc(t.close_time, 'DD') as closedate, 
     extract(hour from t.close_time) as hours, 
     extract(minute from t.close_time) as minutes, 
     count(t.close_time) as total 
from app_account.otrs_ticket t left join 
     app_account.otrs_user u 
     on t.create_user_id=u.id 
where u.id not in (15,7,31,49,50,52,62,66,69,106,17,24,44,32,33,55,22,29,30,47,45,53,70,74,109,1,2,10,23,68,80,20,21,56,108,67) 
group by trunc(t.create_time, 'DD'), trunc(t.close_time, 'DD') 
      extract(hour from t.close_time) as hours, 
      extract(minute from t.close_time) as minutes 
order by trunc(t.create_time, 'DD') desc; 

我不知道什麼是()後close_time，但他們似乎並沒有必要。