2012-06-11 31 views
-2

我在下面的代碼中將IRandomAccessStream轉換爲RandomAccessStreamReference,但是當我看到結果時沒有共享圖像。我該如何處理?將IRandomAccessStream轉換爲RandomAccessStreamReference C#

if (imageFile != null) 
{ 
    using (IRandomAccessStream fileStream = await util.imageFile.OpenAsync(Windows.Storage.FileAccessMode.Read)) 
    { 
     this.imageStreamRef = RandomAccessStreamReference.CreateFromFile(imageFile); 
     this.dataPackageThumbnail = this.imageStreamRef; 
     // this.imageStream = await util.imageFile.OpenAsync(FileAccessMode.Read); 
     await fileStream.FlushAsync(); 
    } 
} 
+1

給出更多細節:) –

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