推塞格呼叫兩次

Question

我正在使用故事板。驗證推入segue我使用「 - （布爾）shouldPerformSegueWithIdentifier :(NSString *）標識符發件人：（id）發件人」這種方法，但它的調用兩次意味着2次點擊後它打開下一個視圖，這種方法也調用2次和我無法找出問題。任何人都可以幫助我解決這個問題。

這裏是我的代碼 -

-(BOOL)shouldPerformSegueWithIdentifier:(NSString *)identifier sender:(id)sender 
{ 
if ([identifier isEqualToString:@"pushTab"]) 
{ 
    if ([emailTxt.text isEqualToString:@""] || [passwordTxt.text isEqualToString:@""])    
    { 
     UIAlertView *alert = [[UIAlertView alloc] initWithTitle:nil message:@"Please    
     put your id or password" delegate:nil cancelButtonTitle:@"OK" 
     otherButtonTitles:nil]; 
     [alert show]; 
     return NO; 
    } 
    else 
    { 
     emailText = emailTxt.text; 
     passwordText = passwordTxt.text; 
     Login *loginModel = [[Login alloc]init]; 
     [ASKevrOperationManager login:loginModel handler:^(id object , NSError *error 
     , BOOL success) 
     { 
      if (success) 
      { 
       flag = true; 
       NSLog(@"Successful data = %@",object); 
      } 
      else 
      { 
       UIAlertView *alert = [[UIAlertView alloc] initWithTitle:nil 
       message:@"Wrong Id or Password" delegate:nil cancelButtonTitle:@"OK" 
       otherButtonTitles:nil]; 
       [alert show]; 
       flag = false; 
       NSLog(@"Invalid Data"); 
      } 
     }]; 
     if (flag == true) { 
      return YES; 
     } 
    } 
} 
return NO; } 

Answer 1

嘗試使用此方法，

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender 
{ 
//Stuff 
}