誤差cudaMemcpy2D

我試圖複製的RGB數據（假設每個是一個int）從主機到device.Here圖像的是我的代碼部分誤差cudaMemcpy2D

int *img_redd,*img_greend,*img_blued;//d denotes device 
int **img_redh,**img_greenh,**img_blueh;// h denotes host 


    //Initialize+ copy values into the arrays pointed by img_redh,img_greenh etc 
    // then Copy the values of RGB into host array <here> 
    //Allocating memory on device below 
    cudaMallocPitch((void**)&img_redd,&pitch1,img_width*sizeof(int),img_height); 
    cudaMallocPitch((void**)&img_greend,&pitch2,img_width*sizeof(int),img_height); 
    cudaMallocPitch((void**)&img_blued,&pitch3,img_width*sizeof(int),img_height); 
    // copy it to CUDA device 
    cudaMemcpy2D(img_redd,pitch1,img_redh[0],img_width*sizeof(int),img_width*sizeof(int),img_height,cudaMemcpyHostToDevice); 
    //I even tried with just img_redh above 
    //Similarly for green and blue

的工作使用cudaMallocPitch罰款但它崩潰的cudamemcpy2d線，開闢了host_runtime.h並指向

static void __cudaUnregisterBinaryUtil(void) 
{ 
    __cudaUnregisterFatBinary(__cudaFatCubinHandle); 
}

我覺得後面的內存分配的邏輯是罰款。任何評論什麼可能導致崩潰？

來源

2011-01-27 Manish

img_redh [0]是否包含指向包含「img_width * img_height * sizeof（int）`連續字節的內存塊的指針？ – tkerwin 2011-01-27 18:30:23

這聽起來像你正在使用一個Iliffe向量爲多維數組img_redh。嘗試使用常規的多維數組（int* img_redh = (int*)malloc(img_width*img_height*sizeof(int)）

來源

2011-01-28 03:51:23 tkerwin

誤差cudaMemcpy2D

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